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2 years ago

Please help me for the braainliest answer

Mathematics

1 answer:

Vinvika [58]2 years ago

5 0

Answer:

TO find the value for the terms, substitute n for the number in the sequence. so

for 1st term n = 1

for 2nd term n =2 etc.

1st Term = 1^2-3 = 1-3 = -2

2nd term = 2^2 - 3 = 4-3 = 1

3rd Term = 3^2 - 3 = 6

10th Term = 10^2 - 3 = 100 - 3 = 97

Hope this helps

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Write the percent as a decimal. 1. 66.7%

Sever21 [200]

Answer:

66.7% = 0.667 in decimal form.

Hope that helps!

7 0

2 years ago

Read 2 more answers

In 2000, the population of Big Springs was 13 thousand. Use the given doubling

trasher [3.6K]

Answer:

The answer is "26179.4".

Step-by-step explanation:

Assume year 2000 as t, that is t =0.

Formula:

$A= A_0e^{rt}$

Where,

$A_0 = \ initial \ pop \\\\r= \ rate \ in \ decimal \\\\t= \ time \ in \ year$

for doubling time,

$r = \frac{log (2)}{t} \\$

$r = \frac{\log (2)}{ 40} \\\\r= \frac{0.301}{40}\\\\r= 0.007$

Given value:

$A = A_0e^{rt} \\\\$

$A_0 = 13000$

$t= 40 \ years$

when year is 2000, t=0 so, year is 2100 year as t = 100.

$A = 13000 \times e^{et}\\\\A = 13000 \times e^{e \times t}\\\\A = 13000 \times e^{0.007 \times 100}\\\\A = 13000 \times e^{0.7}\\\\A= 13000\times 2.0138\\\\A = 26179.4$

7 0

3 years ago

Find the equation of the locus of a point that moves so that its distance from the line 12x-5y-1=0 is always 1 unit.

leonid [27]

Answer-

The equations of the locus of a point that moves so that its distance from the line 12x-5y-1=0 is always 1 unit are

$12x-5y+14=0 \\ 12x-5y-14=0$

Solution-

Let a point which is 1 unit away from the line 12x-5y-1=0 is (h, k)

The applying the distance formula,

$\Rightarrow \left | \frac{12h-5k-1}{\sqrt{12^2+5^2}} \right |=1$

$\Rightarrow \left | \frac{12h-5k-1}{\sqrt{169}} \right |=1$

$\Rightarrow \left | \frac{12h-5k-1}{13} \right |=1$

$\Rightarrow 12h-5k-1=\pm 13$

$\Rightarrow 12h-5k=\pm 14$

$\Rightarrow 12h-5k=14,\ 12h-5k=-14$

$\Rightarrow 12h-5k-14=0,\ 12h-5k+14=0$

$\Rightarrow 12x-5y-14=0,\ 12x-5y+14=0$

Two equations are formed because one will be upper from the the given line and other will be below it.

4 0

2 years ago

ASAP help due today brainliest

umka2103 [35]

B i think.. the product kinda gives it off to me but i’m not sure

5 0

2 years ago

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The following scenarious represent relations that can be graphed. for which of the graphs should the data values be continous ?

Blizzard [7]

Answer:

I would say c

Step-by-step explanation:

5 0

3 years ago