What are the zeros of the function f(x) = x2 + 5x + 5 written in simplest radical form?

Mathematics

1 answer:

satela [25.4K]3 years ago

8 0

Step-by-step explanation:

$x = \frac{ - b + - \sqrt{ {b}^{2} - 4ac } }{2a} \\ x = \frac{ - 5 + - \sqrt{ {5}^{2} - 4(5) } }{2} \\ x = \frac{ - 5 + - \sqrt{25 - 20} }{2} \\ x = \frac{ - 5 + - \sqrt{5} }{2}$

Therefore, the zeroes would be:

$x1 = \frac{ - 5 + \sqrt{5} }{2} \\ x2 = \frac{ - 5 - \sqrt{5} }{2}$

You might be interested in

За – 6а + 2 = 8а + 20 – 5а

Luda [366]

Answer:

a = -3

Step-by-step explanation:

3a - 6a + 2 = 8a + 20 - 5a

Combine Like Terms

-3a + 2 = 3a + 20

-2 -2

-------------------------------------

-3a = 3a + 18

-3a -3a

-------------------------------------

-6a = 18

---- ----

-6 -6

a = -3

4 0

2 years ago

A spacecraft is traveling with a velocity of v0x = 5320 m/s along the +x direction. Two engines are turned on for a time of 739

OlgaM077 [116]

Answer:

The velocities after 739 s of firing of each engine would be 6642.81 m/s in the x direction and 5306.02 in the y direction

Step-by-step explanation:

For a constant acceleration: $v_{f}=v_{0}+at$ , where $v_{f}$ is the final velocity in a direction after the acceleration is applied, $v_{0}$ is the initial velocity in that direction before the acceleration is applied, a is the acceleration applied in such direction, and t is the amount of time during where that acceleration was applied.
<em>Then for the x direction</em> it is known that the initial velocity is $v_{0x} =$ 5320 m/s, the acceleration (the applied by the engine) in x direction is $a_{x}$ 1.79 m/s2 and, the time during the acceleration was applied (the time during the engines were fired) of the is 739 s. Then: $v_{fx}=v_{0x}+a_{x}t=5320\frac{m}{s} +1.79\frac{m}{s^{2} }*739s=6642.81\frac{m}{s}$
In the same fashion, <em>for the y direction</em>, the initial velocity is $v_{0y} =$ 0 m/s, the acceleration in y direction is $a_{y}$ 7.18 m/s2, and the time is the same that in the x direction, 739 s, then for the final velocity in the y direction: $v_{fy}=v_{0y}+a_{y}t=0\frac{m}{s} +7.18\frac{m}{s^{2} }*739s=5306.02\frac{m}{s}$