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Masteriza [31]
3 years ago
14

What are the zeros of the function f(x) = x2 + 5x + 5 written in simplest radical form?

Mathematics
1 answer:
satela [25.4K]3 years ago
8 0

Step-by-step explanation:

x =  \frac{ - b +  -  \sqrt{ {b}^{2} - 4ac } }{2a}  \\ x =  \frac{ - 5 +  -   \sqrt{ {5}^{2} - 4(5) } }{2}  \\ x =  \frac{ - 5 +  -  \sqrt{25 - 20} }{2}  \\ x =  \frac{ - 5 +  -  \sqrt{5} }{2}

Therefore, the zeroes would be:

x1 =  \frac{ - 5 +  \sqrt{5} }{2}  \\ x2 =  \frac{ - 5 -  \sqrt{5} }{2}

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