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3 years ago

What are the zeros of the function f(x) = x2 + 5x + 5 written in simplest radical form?

Mathematics

1 answer:

satela [25.4K]3 years ago

8 0

Step-by-step explanation:

$x = \frac{ - b + - \sqrt{ {b}^{2} - 4ac } }{2a} \\ x = \frac{ - 5 + - \sqrt{ {5}^{2} - 4(5) } }{2} \\ x = \frac{ - 5 + - \sqrt{25 - 20} }{2} \\ x = \frac{ - 5 + - \sqrt{5} }{2}$

Therefore, the zeroes would be:

$x1 = \frac{ - 5 + \sqrt{5} }{2} \\ x2 = \frac{ - 5 - \sqrt{5} }{2}$

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Alenkinab [10]

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Yakvenalex [24]

Answer:

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W = 1/2

Substitute it into the expression,

3 = L * 1/2

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L = 3/2 ft²

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3 years ago

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3 years ago

Choose the expression that is equal to 28.3

tamaranim1 [39]

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2 years ago

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Suppose you know that Mr. and Mrs. Vincent have at most eight children. One day you happen to meet two girls who were the Vincen

lianna [129]

Answer:

The number of children are 4 out of which 3 are girls

Step-by-step explanation:

Data provided in the question:

P(Two randomly selected children are girls) = $\frac{1}{2}$

now,

let the number of children be 'n'

the number of girls be 'x'

thus,

P(Two randomly selected children are girls) = $\frac{^xC_2}{^nC_2}$ = $\frac{1}{2}$

also,

$^nC_r$ = $\frac{n!r!}{(n-r)!}$

thus,

$\frac{\frac{x!2!}{(x-2)!}}{\frac{n!2!}{(n-2)!}}$ = $\frac{1}{2}$

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