Question

What are the zeros of the function f(x) = x2 + 5x + 5 written in simplest radical form?

Answer 1

Step-by-step explanation:

$x = \frac{ - b + - \sqrt{ {b}^{2} - 4ac } }{2a} \\ x = \frac{ - 5 + - \sqrt{ {5}^{2} - 4(5) } }{2} \\ x = \frac{ - 5 + - \sqrt{25 - 20} }{2} \\ x = \frac{ - 5 + - \sqrt{5} }{2}$

Therefore, the zeroes would be:

$x1 = \frac{ - 5 + \sqrt{5} }{2} \\ x2 = \frac{ - 5 - \sqrt{5} }{2}$