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Aneli [31]
3 years ago
14

Let T be the statement: The sum of any two rational numbers is rational. Then T is true, but the following "proof is incorrect.

Find the mistake. "Proof by contradiction: Suppose not. That is, suppose that the sum of any two rational numbers is not rational. This means that no matter what two rational numbers are chosen their sum is not rational. Now both 1 and 3 are 1/1 and 3 3/1, and so both are ratios of integers with rational because 1 a nonzero denominator. Hence, by a supposition, the sum of 1 and 3, which is 4, is not rational. But 4 is rational because 4 4/1 , which is a ratio of integers with a nonzero denominator. Hence 4 is both rational and not rational, which is a contradiction. This contradiction shows that the supposition is false and hence statement T is true.
Computers and Technology
1 answer:
ikadub [295]3 years ago
4 0

Answer:

the mistake is in the first statement.

Explanation:

Now lets us put the statement into consideration:

"The sum of any two rational numbers is irrational"

The negation is: " there exists a pair of rational numbers whose sum is irrational". (Existence of at least one of such a pair).

The negation is not "the sum of any two rational numbers is irrational"

Therefore the mistake is in the first statement and it is due to incorrect negation of the proof.

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What is included on the HP PC Hardware Diagnostics 3-in-1 USB Key that allows you to recover systems that cannot boot?
algol13

Answer:

HP PC Hardware Diagnostics UEFI

Explanation:

The 3-in-1 HP PC Hardware Diagnostics UEFI USB Key helps the client distinguish potential software, hardware, and Operating System issues. Both older and newer HP Desktop and Laptop PCs come with this tool installed. By default, it operates outside the OS to detach equipment issues from other system issues. In the event you do not have it pre-installed, you can get it from the official HP site.

3 0
4 years ago
To avoid potential documentary errors and security leaks, the configuration of firewalls should not be documented unless strictl
Zolol [24]

Answer: False

Explanation:

 The given statement is false, as the configuration of the firewall, operational and administration procedure must be documented.

The configuration of multiple firewall are identical and the integrity and also performance of the configuration firewall files are check on the regularly bases.

It is basically used to avoid the security leaks and the documentation errors so it is necessary that it should be check regularly so that it can easily implement without any interrupt occurrence.

8 0
3 years ago
Write a program that will open the file random.txt and calculate and display the following: A. The number of numbers in the file
Rama09 [41]

Answer:

Here is the C++ program:

#include <iostream>  //to use input output functions

#include <fstream>  //to manipulate files

using namespace std;  //to identify objects like cin cout

int main(){  //start of main function

  ifstream file;   //creates an object of ifstream

   file.open("random.txt"); //open method to open random.txt file using object file of ifstream

       

    int numCount = 0;  //to store the number of all numbers in the file          

    double sum = 0;   //to store the sum of all numbers in the file

    double average = 0.0;   //to store the average of all numbers in the file

    int number ; //stores numbers in a file

                 

        if(!file){   //if file could not be opened

           cout<<"Error opening file!\n";    }   //displays this error message

       

       while(file>>number){   //reads each number from the file till the end of the file and stores into number variable

           numCount++; //adds 1 to the count of numCount each time a number is read from the file          

           sum += number;  }  //adds all the numbers and stores the result in sum variable

           average = sum/numCount;  //divides the computed sum of all numbers by the number of numbers in the file

     

       cout<<"The number of numbers in the file: "<<numCount<<endl;  //displays the number of numbers

       cout<<"The sum of all the numbers in the file: "<<sum<<endl;  //displays the sum of all numbers

       cout<<"The average of all the numbers in the file: "<< average<<endl;  //displays the average of all numbers

       file.close();     }  //closes the file    

   

Explanation:

Since the random.txt is not given to check the working of the above program, random.txt is created and some numbers are added to it:

35

48

21

56

74

93

88

109

150

16

while(file>>number) statement reads each number and stores it into number variable.

At first iteration:

35 is read and stored to number

numCount++;  becomes

numCount = numCount + 1

numCount = 1      

sum += number; this becomes:

sum = sum + number

sum = 0 + 35

sum = 35

At second iteration:

48 is read and stored to number

numCount++;  becomes

numCount = 1+ 1

numCount = 2    

sum += number; this becomes:

sum = sum + number

sum = 35 + 48

sum = 83

So at each iteration a number is read from file, the numCount increments to 1 at each iteration and the number is added to the sum.

At last iteration:

16 is read and stored to number

numCount++;  becomes

numCount = 9 + 1

numCount = 10    

sum += number; this becomes:

sum = sum + number

sum = 674 + 16

sum = 690

Now the loop breaks and the program moves to the statement:

       average = sum/numCount;  this becomes:

       average = 690/10;

       average = 69

So the entire output of the program is:

The number of numbers in the file: 10                                                                                                           The sum of all the numbers in the file: 690                                                                                                     The average of all the numbers in the file: 69

The screenshot of the program and its output is attached.

5 0
4 years ago
Use the variables k, d, and s so that they can read three different values from standard input--an integer, a double, and a stri
Nat2105 [25]

Answer:

The c++ program to implement the given scenario is shown below.

#include <iostream>

using namespace std;

int main() {

   // variables declared as mentioned

   int k;

   double d;

   string s;

   cout << " Enter an integer value, a double value, a string value in the mentioned order " << endl;

   cin >> k >> d >> s;

   // variables printed in reverse order

   cout << " Reverse order " << endl;

   cout << s << " " << d << " " << k << endl;

   // variables printed in original order

   cout << " Original order " << endl;

   cout << k << " " << d << " " << s << endl;

   return 0;

}

OUTPUT

Enter an integer value, a double value, a string value in the mentioned order  

12 45.67 brainly

Reverse order  

brainly 45.67 12

Original order  

12 45.67 brainly

Explanation:

1. All the variables are declared as mentioned in the question.

int k;

   double d;

   string s;

2. The user is prompted to enter values for integer, double and string variables respectively. The input is accepted in the order mentioned above.

cin >> k >> d >> s;

3. The input is accepted in a single line since this is mentioned in the scenario that variables should be printed in the order in which they are read.

4. These variables are displayed to the standard output in reverse order – string, double, integer. The variables are displayed with exactly one space in between them.

cout << s << " " << d << " " << k << endl;

5. Then, variables are displayed in the original order – integer, double, string. The variables are displayed with exactly one space in between them.

cout << k << " " << d << " " << s << endl;

7 0
3 years ago
A=3<br> b = 2<br> print (a ** b)<br> What is output?
Lady bird [3.3K]

Answer: ( 3**2)

Explanation: honestly I can't help you. Try google it is waiting for you with open harms.  

6 0
3 years ago
Read 2 more answers
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