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3 years ago

What influences combined to produce Russian culture?

1 answer:

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<span>Russian culture has a Slavic base (language, folklore). It was influenced by Scandinavians (Viking times) mostly in fight technics, weapons, ship-building and establishing trade unions. Than Russian culture was greatly influenced by Byzantine Empire (in religion, book issuing and iconography). Then by Mongols (during 3 centuries of invasion, again in weapons, fight technics, laws and a little in state system).
BTW can i have the brainless answer....plz...</span>

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CAN SOMEONE HELP ME WITH THESE QUESTIONS PLEASE!?

sukhopar [10]

Answer:

Step-by-step explanation:

$(c+9)^2=64=8^2\\$

c+9=±8

either c=8-9=-1

c=-8-9=-17

so c=-1,-17

8x^2-3=2

8x^2=5

$x^2=\frac{5}{8}=\frac{10}{16}$

$x=±\frac{\sqrt{10}}{4}$

so A

$x^2+4x+4=18\\(x+2)^2=9*2\\x+2=3\sqrt{2} \\x=-2 ±3\sqrt{2}$

so D

8 0

3 years ago

What is the partial product of 4.6 x 3.5

PIT_PIT [208]

The partial product of 4.6×3.5 is 16.1

7 0

3 years ago

Read 2 more answers

Lynn asked six friends how many cars their parents own. She recorded 1, 1, 2, 2, 2, and 4 cars. What is the mean absolute deviat

Daniel [21]

If number of cars recorded by Lynn is 1, 1, 2, 2, 2, and 4 cars then the mean absolute deviation of the number of cars is 0.7

<h3>What is the mean absolute deviation?</h3>

The mean absolute deviation of a data set is the average of the absolute deviations from a central point .

Data we have is

1,1,2,2,2,4

Mean can be calculated as

$&\text { Mean }=\frac{1+1+2+2+2+4}{6}\\ \\&\text { Mean }=\frac{12}{6} \\\\&\text { Mean }=2$

Absolute value between the data points and mean can be calculated as :

$\begin{aligned}&|1-2|=1 \\&|1-2|=1 \\&|2-2|=0 \\&|2-2|=0 \\&|2-2|=0 \\&|4-2|=2\end{aligned}$

Now mean absolute deviation can be calculated as :

$\begin{aligned}&\frac{1+1+0+0+0+2}{6} \\\\&=\frac{4}{6} \\\\&=0.66\end{aligned}$$$

Rounding to nearest ten

mean absolute deviation=0.7

If number of cars recorded by Lynn is 1, 1, 2, 2, 2, and 4 cars then the mean absolute deviation of the number of cars is 0.7

To learn more about mean absolute deviation visit :brainly.com/question/17381861

6 0

2 years ago

Helppppppppppppppppppppppppppppppppppppppppppp meeeeee

Zigmanuir [339]

Answer:

Angle A = 19

Step-by-step explanation:

Vertical angles are congruent ( equal to each other )

If angle A and angle B are vertical angles and vertical angles are congruent then angle A = angle B

If angle A = 3x + 13 and angle B = 5x + 9 then 3x + 13 = 5x + 9

( Note that we just created an equation that we can use to solve for x )

We now solve for x using the equation created

3x + 13 = 5x + 9

Step 1 subtract 3x from both sides

Outcome: 13 = 2x + 9

Step 2 subtract 9 from both sides

Outcome: 4 = 2x

Step 3 divide both sides by 2

Outcome: x = 2

Now to find Angle A

All we have to do to find the measure of angle a is simply substitute 2 for x in it's given expression ( 3x + 13 )

Substitute 2 for x

Angle A = 3(2) + 13

Multiply

Angle A = 6 + 13

Add

Angle a = 19

3 0

3 years ago

Evaluate the integral ∫2032x2+4dx. Your answer should be in the form kπ, where k is an integer. What is the value of k? (Hint: d

faltersainse [42]

Here is the correct computation of the question;

Evaluate the integral :

$\int\limits^2_0 \ \dfrac{32}{x^2 +4} \ dx$

Your answer should be in the form kπ, where k is an integer. What is the value of k?

(Hint: $\dfrac{d \ arc \ tan (x)}{dx} =\dfrac{1}{x^2 + 1}$ )

k = 4

(b) Now, lets evaluate the same integral using power series.

$f(x) = \dfrac{32}{x^2 +4}$

Then, integrate it from 0 to 2, and call it S. S should be an infinite series

What are the first few terms of S?

Answer:

(a) The value of k = 4

(b)

$a_0 = 16\\ \\ a_1 = -4 \\ \\ a_2 = \dfrac{12}{5} \\ \\a_3 = - \dfrac{12}{7} \\ \\ a_4 = \dfrac{12}{9}$

Step-by-step explanation:

(a)

$\int\limits^2_0 \dfrac{32}{x^2 + 4} \ dx$

$= 32 \int\limits^2_0 \dfrac{1}{x+4}\ dx$

$=32 (\dfrac{1}{2} \ arctan (\dfrac{x}{2}))^2__0$

$= 32 ( \dfrac{1}{2} arctan (\dfrac{2}{2})- \dfrac{1}{2} arctan (\dfrac{0}{2}))$

$= 32 ( \dfrac{1}{2}arctan (1) - \dfrac{1}{2} arctan (0))$

$= 32 ( \dfrac{1}{2}(\dfrac{\pi}{4})- \dfrac{1}{2}(0))$

$= 32 (\dfrac{\pi}{8}-0)$

$= 32 ( (\dfrac{\pi}{8}))$

$= 4 \pi$

The value of k = 4

(b) $\dfrac{32}{x^2+4}= 8 - \dfrac{3x^2}{2^1}+ \dfrac{3x^4}{2^3}- \dfrac{3x^6}{2x^5}+ \dfrac{3x^8}{2^7} -... \ \ \ \ \ (Taylor\ \ Series)$

$\int\limits^2_0 \dfrac{32}{x^2+4}= \int\limits^2_0 (8 - \dfrac{3x^2}{2^1}+ \dfrac{3x^4}{2^3}- \dfrac{3x^6}{2x^5}+ \dfrac{3x^8}{2^7} -...) dx$

$S = 8 \int\limits^2_0dx - \dfrac{3}{2^1} \int\limits^2_0 x^2 dx + \dfrac{3}{2^3}\int\limits^2_0 x^4 dx - \dfrac{3}{2^5}\int\limits^2_0 x^6 dx+ \dfrac{3}{2^7}\int\limits^2_0 x^8 dx-...$

$S = 8(x)^2_0 - \dfrac{3}{2^1*3}(x^3)^2_0 +\dfrac{3}{2^3*5}(x^5)^2_0- \dfrac{3}{2^5*7}(x^7)^2_0+ \dfrac{3}{2^7*9}(x^9)^2_0-...$

$S= 8(2-0)-\dfrac{1}{2^1}(2^3-0^3)+\dfrac{3}{2^3*5}(2^5-0^5)- \dfrac{3}{2^5*7}(2^7-0^7)+\dfrac{3}{2^7*9}(2^9-0^9)-...$

$S= 8(2-0)-\dfrac{1}{2^1}(2^3)+\dfrac{3}{2^3*5}(2^5)- \dfrac{3}{2^5*7}(2^7)+\dfrac{3}{2^7*9}(2^9)-...$

$S = 16-2^2+\dfrac{3}{5}(2^2) -\dfrac{3}{7}(2^2) + \dfrac{3}{9}(2^2) -...$

$S = 16-4 + \dfrac{12}{5}- \dfrac{12}{7}+ \dfrac{12}{9}-...$

$a_0 = 16\\ \\ a_1 = -4 \\ \\ a_2 = \dfrac{12}{5} \\ \\a_3 = - \dfrac{12}{7} \\ \\ a_4 = \dfrac{12}{9}$

6 0

3 years ago