You plug in 7 for f(x) so you solve for 7=2x+3. The final answer is x=2
Answer:
46/117
Step-by-step explanation:
Answer:
Y'=3xy-3x-12
Y'=F(-2,-1)=0
Step-by-step explanation:
The function of the equation at the point (-2,-1)
is where the equation make the function go to zero:
Y'=3xy-3x-12
Y'=F(-2,-1)=[3(-2)(-1)]-[3(-1)]-12
F(-2,-1)=[6]-[-6]-12
F(-2,-1)=6+6-12
F(-2,-1)=12-12
F(-2,-1)=0
Solving for y
3xy-3x-12=0
y=4/x+x
Making y=0
![\frac{4}{x}+x=0](https://tex.z-dn.net/?f=%5Cfrac%7B4%7D%7Bx%7D%2Bx%3D0)
![x^{2} =-4](https://tex.z-dn.net/?f=x%5E%7B2%7D%20%3D-4)
![x=-2](https://tex.z-dn.net/?f=x%3D-2)
So the values make the function go to zero