Answer:
5 kg
Step-by-step explanation:
1 and 4,2 and 3 are the alternate interior angles
Answer:
It takes less time sending 5 letters the traditional way with a probability of 36.7%.
Step-by-step explanation:
First we must take into account that:
- The traditional method is distributed X ~ Poisson(L = 1)
- The new method is distributed X ~ Poisson(L = 5)

Where L is the intensity in which the events happen in a time unit and x is the number of events.
To solve the problem we must calculate the probability of events (to send 5 letters) in a unit of time for both methods, so:
- For the traditional method:

- For the new method:

According to this calculations we have a higher probability of sending 5 letters with the traditional method in a unit of time, that is 36.7%. Whereas sending 5 letters with the new method is less probable in a unit of time. In other words, we have more events per unit of time with the traditional method.
Answer:
Greatest sack = 42
1 candy bar and 3 lollipops
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Step-by-step explanation:
Represent Candy bars with C and Lollipops with L


Solving (a): Greatest number of treat sacks
To solve this, we simply calculate the GCF of C and L


Hence, the GCF is


Hence, greatest number of sack is 42
Solving (b): Number of treat in each sack.
To do this, we simply divide the number of C and L by the calculated GCF
For C:



For L:



<em>Hence, 1 candy bar and 3 lollipops</em>
The answer is: " (x + 2) " .
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