Answer: B
Explanation: And why are you searching up the answers if thats a MapTest -_-
In the ring of fire
It is called that because of all the volcanoes there
Answer:
The percentage of the population that is heterozygous for this trait is 48%
Explanation:
They are two alleles, the phenylthiocarbamide tasters (PTC) and the non phenylthiocarbamide tasters (non PTC). PTC testers are dominant and non PTC tasters are recessive.
let the frequency of the dominant allele(A) be p
and the frequency of the recessive allele(a) be q
We are told that 64 percent of people living in a remote, isolated mountain village can taste phenylthiocarbamide (PTC) and must, therefore, have at least one copy of the dominant PTC taster allele (that is AA and Aa)
Frequency of AA = p², Frequency of Aa = 2pq and Frequency of aa = q²
Therefore p² + 2pq = 64% = 0.64
According to Hardy–Weinberg:
p² + 2pq + q² = 1 and
p + q = 1
Since p² + 2pq = 0.64
∴ 0.64 + q² = 1
q² = 1 - 0.64 = 0.36
q = √0.36 = 0.6
Since p + q = 1
p = 1 - q = 1 - 0.6 = 0.4
The frequency of heterozygous = 2pq = 2 × 0.4 × 0.6 = 0.48
Therefore the percentage of the population that is heterozygous for this trait is 48%
Mitosis is split into 4 phases.
P - prophase
M - metaphase
A - anaphase
T - telophase
During Metaphase, Chromosomes align singly along the metaphase plate.
During Anaphase, kinetochore microtubules shortens and non-kinetochore microtubules lengthens, allowing the chromosomes' centromeres to separate.
Therefore, the answer is anaphase.
P. S. centromeres separates, not split.
Answer:
Hi, there your answer will be C. to convert carbon dioxide into sugars(glucose)
Explanation:
