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torisob [31]
3 years ago
9

Find the slope of the line above

Mathematics
2 answers:
Varvara68 [4.7K]3 years ago
4 0
Someone is answering good luck
zzz [600]3 years ago
4 0

Answer:

3/5

Step-by-step explanation:

Pick two points that are easy to read. pints that are easy to read are on the intersection of grid lines.

For example, pick (-2, 0) and (3, 3).

slope = rise/run

Rise is a vertical distance.

Run is a horizontal distance.

Start at (-2, 0). To go to (3, 3) by using only horizontal and vertical segments, go up 3 unit. Now go right 5 units.

The rise is 3. The runs is 5.

slope = rise/run = 3/5

Answer: 3/5

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What are these numbers in order from greatest to least
DerKrebs [107]
Answer : Square root of 21 , -4 2/3, -30/7 , -31/6 .

Explanation :

-4 2/3 = -10/3 = -3.3333
Square root of 21 = 4.58258
-31/6 = -5.1666
-30/7 = 4.2857

And arrange them from greatest to least and there we have the answer.

Hope this helps you understand !!!!
4 0
3 years ago
A cable car starts off with n riders. The times between successive stops of the car are independent exponential random variables
nikitadnepr [17]

Answer:

The distribution is \frac{\lambda^{n}e^{- \lambda t}t^{n - 1}}{(n - 1)!}

Solution:

As per the question:

Total no. of riders = n

Now, suppose the T_{i} is the time between the departure of the rider i - 1 and i from the cable car.

where

T_{i} = independent exponential random variable whose rate is \lambda

The general form is given by:

T_{i} = \lambda e^{- lambda}

(a) Now, the time distribution of the last rider is given as the sum total of the time of each rider:

S_{n} = T_{1} + T_{2} + ........ + T_{n}

S_{n} = \sum_{i}^{n} T_{n}

Now, the sum of the exponential random variable with \lambda with rate \lambda is given by:

S_{n} = f(t:n, \lamda) = \frac{\lambda^{n}e^{- \lambda t}t^{n - 1}}{(n - 1)!}

5 0
3 years ago
HELP!!! URGENT!!! I WILL GIVE BRAINLEIST THING ​
lisov135 [29]

Answer:

Horizontal distance = 0 m and 6 m

Step-by-step explanation:

Height of a rider in a roller coaster has been defined by the equation,

y = \frac{1}{3}x^{2}-2x+8

Here x = rider's horizontal distance from the start of the ride

i). y=\frac{1}{3}x^{2}-2x+8

      =\frac{1}{3}(x^{2}-6x+24)

      =\frac{1}{3}[x^{2}-2(3x)+9-9+24]

      =\frac{1}{3}[(x^{2}-2(3x)+9)+15]

      =\frac{1}{3}[(x-3)^2+15]

      =\frac{1}{3}(x-3)^2+5

ii). Since, the parabolic graph for the given equation opens upwards,

    Vertex of the parabola will be the lowest point of the rider on the roller coaster.

    From the equation,

    Vertex → (3, 5)

    Therefore, minimum height of the rider will be the y-coordinate of the vertex.

    Minimum height of the rider = 5 m

iii). If h = 8 m,

    8=\frac{1}{3}(x-3)^2+5

    3=\frac{1}{3}(x-3)^2

    (x - 3)² = 9

    x = 3 ± 3

    x = 0, 6 m

    Therefore, at 8 m height of the roller coaster, horizontal distance of the rider will be x = 0 and 6 m

6 0
3 years ago
The number 28 please somebody help me...
MArishka [77]
Where is the persons info
8 0
3 years ago
ANSWER ASAP<br> THANKS<br> ...............
mylen [45]

Answer:

250

Step-by-step explanation:

5*5=25

25*10=250

+$++$$+$

6 0
3 years ago
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