Answer: Question 1
a)5.47
b)4.53
Step-by-step explanation:
Answer:
Let the Dulcina's collection be 'x'
Let the Tremaine collection be 'x-39'
x + x - 39 =129
2x = 129 +39
2x = 168
x = 168/2
x = 84
Dulcina's collection = x = 84
Tremaine's collection = x - 39 = 84 - 39 = 45
Hello from MrBillDoesMath!
Answer:
Positive x-intercept = + sqrt(3)
Negative x-intercept = - sqrt(3)
Discussion:
Generally, the x-intercept of a function g(x) occurs where g(x) = 0. In our case this is
g(x) = 0 =>
3x^2 - 9 = 0 => (add 9 to both sides of the equation)
3 x^2 = 9 => (divide both sides by 3)
x^2 = 9/3 = 3 =>
x = +\- sqrt (3)
Positive x-intercept = + sqrt(3)
Negative x-intercept = - sqrt(3)
Thank you,
MrB
The length of the base is 6. You can use the formula b=a/h to find the base. <span />
Answer:
x^4 - 2x^3 - 29x^2 - 42x
Step-by-step explanation:
Equal all the zeros to x then move them over.
x=7,x=-3,x=0,x=-2
x-7,x+3,x+0,x+2
Then multiply each factor
(x-7)(x+3)(x)(x+2)
x^4 - 2x^3 - 29x^2 - 42x
