A number that makes a statement true is the solution
The value of A is RM 205.
Since Billy gave money to a charity over a 20 year period, from Year 1 to Year 20 inclusive, and he gave RM150 in Year 1, RM160 in Year 2, RM170 in year 3, and so on, and Kevin also gave money to the charity over the same 20 years period, but he gave RMA im Year 1 and the amount of money he gave each year increased, forming an arithmetic sequence with common difference RM30, and the total amount of money that Kevin gave over 20 years period was twice the total amount of money that Billy gave, to calculate the value of A the following calculation must be performed:
- Billy = (150 x 20) + 10 + 20 + 30 + 40 + 50 + 60 + 70 + 80 + 90 + 100 + 110 + 120 + 130 + 140 + 150 + 160 + 170 + 180 + 190
- Billy = (150 x 20) + 1900
- Billy = 3000 + 1900
- Billy = 4900
- Kevin = (9800 - (30 + 60 + 90 + 120 + 150 + 180 + 210 + 240 + 270 + 300 + 330 + 360 + 390 + 420 + 450 + 480 + 510 + 540 + 570)) / 20
- Kevin = (9800 - 5700) / 20
- Kevin = 4100/20
- Kevin = 205
Therefore, the value of A is RM 205.
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Y directly proportional to X
Y=kX ( k =constant)
30=6k
k=30/6
k=5
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Answer:
5.78% probability that exactly 2 of them use their smartphones in meetings or classes.
Step-by-step explanation:
For each adult, there are only two possible outcomes. Either they use their smarthphone in meetings or classes, or they do not. The probability of an adult using their smartphone on meetings or classes is independent of other adults. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
In which is the number of different combinations of x objects from a set of n elements, given by the following formula.
And p is the probability of X happening.
63% use them in meetings or classes.
This means that
7 adult smartphone users are randomly selected
This means that
Find the probability that exactly 2 of them use their smartphones in meetings or classes.
This is P(X = 2).
5.78% probability that exactly 2 of them use their smartphones in meetings or classes.