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expeople1 [14]
4 years ago
5

Solve for x in the equatuion 2x^2+3x-7=x^2+5x+39

Mathematics
2 answers:
kenny6666 [7]4 years ago
6 0

Answer:

x_{1 = 1 - \sqrt 47, x_{2 = 1 + \sqrt47

Step-by-step explanation:

Rama09 [41]4 years ago
5 0
I’m
Trynaaa ask a questionnnnnnn
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Simplify the expression by combining like terms 5X + 9Y + 12 + X +2 (steps and tips also)
nika2105 [10]
The final would be
6X+9Y+14
How?
You combine similar numbers. You can't combine 5X with 2 but you can combine 5X with X
also just the letter X means it is a one.
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1+1(giveing away ponits )
s344n2d4d5 [400]

Answer:

2 yay

Step-by-step explanation:

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If the area of a square is 169, what is the length of its side
Svet_ta [14]
--------------------
If the area of a square is 169, what is the length of its side?

13 = sqrt169
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4 0
3 years ago
Solve 4 by 216 raise to minus 2 by 3 + 1 by 256 raise to 3 by 4 + 2 by 243 raise to 1 by 5​
olchik [2.2K]

Answer:

214....

Step-by-step explanation:

If the question is : solve 4 by 216 raise to minus 2 by 3 + 1 by 256 raise to minus 3 by 4 + 2 by 243 raise to minus 1 by 5​

The given expression can be written as:

4/(216)-2/3+1/(256)-3/4+2/(243)-1/5

This expression has three terms.

Notice that the exponents are negative:

We will change the division into multiplication so that the exponents will become positive;

4*(216)^2/3+ 1*(256)^3/4+ 2*(243)^1/5

If we multiply 6 three times it will give us 6^3=6*6*6=216

If we multiply 4 four  times it will give us 4^4=4*4*4*4=256

If we multiply 3 five times it will give us 3^5=3*3*3*3*3=243

So we will write it as:

=4*(6^3)^2/3+ 1(4^4)3/4 +2(3^5)^1/5

=4(6)^2+(4)^3+2(3)

=4*36+64+6

=144+64+6

=214

The answer is 214....

7 0
3 years ago
Use the given pair of functions to find and simplify expressions for the following functions and state the domain of each using
Tamiku [17]

Answer:

Given functions,

f(x) = 3 - x^2

g(x) = \sqrt{x}+1

Since, by the compositions of functions,

1. (g◦f)(x) = g(f(x))

=g(3-x^2)

=\sqrt{3-x^2}+1

Since, (g◦f) is defined,

If 3 - x² ≥ 0

⇒ 3 ≥ x²

⇒ -√3 ≤ x ≤ √3

Thus, Domain = [-√3, √3]

2. (f◦g)(x) = f(g(x))

=f(\sqrt{x}+1)

=3-(\sqrt{x}+1)^2

Since, (g◦f) is defined,

If  x ≥ 0

Thus, Domain = [0, ∞)

3. (f◦f)(x) = f(f(x))

=f(3-x^2)

=3-(3-x^2)^2

=3-9-x^4+6x^2

=-6+6x^2-x^4

Since, (f◦f) is a polynomial,

We know that,

A polynomial is defined for all real value of x,

Thus, Domain = (-∞, ∞)

8 0
3 years ago
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