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3 years ago

Find the common ratio of the geometric sequence: −320,80,−20,5,…

2 answers:

soldier1979 [14.2K]3 years ago

8 0

With geometric sequences, if you divide a term by the term before it you'll get the common ratio. That's how they are all constructed, and in this problem:

$\frac{80}{-320}=-\frac{1}{4}$

So -1/4 is our common ratio.

Ivan3 years ago

3 0

This is a geometric sequence since there is a common ratio between each term. In this case, multiplying the previous term in the sequence by 14 1 4 gives the next term.

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Use the distributive property to find the product.

VladimirAG [237]

A Is your answer :D

W^2 + 2W + 3

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3 years ago

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What could be the next statement that Ivan makes his proof?

natali 33 [55]

Answer: Choice A) Triangle ABC is similar to triangle ACD by AA

AA stands for Angle Angle. Specifically it means we need 2 pairs of congruent angles between the two triangles in order to prove the triangles similar. Your book might write "AA similarity" instead of simply "AA".

For triangles ABC and ACD, we have the first pair of angles being A = A (angle A shows up twice each in the first slot). The second pair of congruent angles would be the right angles for triangle ABC and ACD, which are angles C and D respectively.

We can't use AAS because we don't know any information about the sides of the triangle.

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3 years ago

If the diameter of the circle is 24 cm, find its area correct to 1 decimal place.

Blababa [14]

Answer:

452.4 cm^2

Step-by-step explanation:

Use the area formula A = πr². With d = 24 cm, r = 12 cm, and so the desired area is

A = π(144 cm^2) = 452.4 cm^2

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3 years ago

The probability that a grader will make a marking error on any particular question of a multiple-choice exam is 0.15. If there a

sashaice [31]

Answer:

$P(X=0)=(10C10)(0.15)^{0} (1-0.15)^{10-0}=0.1969$

$P(X \geq 1)= 1-P(X$

$P(X=0)=(nCn)(p)^{0} (1-p)^{n-0}=(1-p)^n$

$P(X \geq 1)= 1-P(X$

Step-by-step explanation:

Previous concepts

A Bernoulli trial is "a random experiment with exactly two possible outcomes, "success" and "failure", in which the probability of success is the same every time the experiment is conducted". And this experiment is a particular case of the binomial experiment.

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

The complement rule is a theorem that provides a connection between the probability of an event and the probability of the complement of the event. Lat A the event of interest and A' the complement. The rule is defined by: $P(A)+P(A') =1$

Solution to the problem

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=10, p=0.15)$

what is the probability that no errors are made?

For this case means that all the questions were correct so we want this probability:

$P(X=0)=(10C10)(0.15)^{0} (1-0.15)^{10-0}=0.1969$

what is the probability that at least one error made?

For this case we want this probability:

$P(X \geq 1)$

And we can use the complement rule:

$P(X \geq 1)= 1-P(X$

If there are n questions and the probability of a marking error is p rather than 0.15, give expressions for the probabilities of no errors and at least one error

$P(X=0)=(nCn)(p)^{0} (1-p)^{n-0}=(1-p)^n$

$P(X \geq 1)= 1-P(X$

8 0

3 years ago

What forms of the following equation in?<br><br> y+5=7(x−3)

skelet666 [1.2K]

I think it would be -26

3 0

3 years ago

Read 2 more answers