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BartSMP [9]
3 years ago
13

Is counterclockwise around the triangle with vertices (0, 0), (1, 0), and (1, 4)?

Mathematics
1 answer:
lubasha [3.4K]3 years ago
4 0
Strange question but I'd say yes as you move point to point.    


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i lost my old brainly account name it was called official norths :( i forgot the password i will love if you help me with this p
nalin [4]

Answer:

86° Fahrenheit

Step-by-step explanation:

F=1.8C + 32

C=30°

Plugging into the formula:

F=1.8*30+32\\F=54+32\\F=86

The Fahrenheit for 30° Celsius using the given formula is 86° Fahrenheit.

7 0
3 years ago
Read 2 more answers
X + 3x² – 28x <br><br> Can you guys help me solve this in ax^2+bx+c <br> Thank you thank you
Molodets [167]

Answer:

3x²+(-27x) +0

Step-by-step explanation:

The given expression is :

x + 3x² – 28x

We need to solve this in the form of ax²+bx+c.

we can write the given expression as :

3x²-28x+x = 3x²-27x

= 3x²+(-27x) +0

If we compare the given expression with the general expression, we find that,

a = 3, b = -27 and c = 0

Hence, the required equation is 3x²+(-27x) +0.

3 0
3 years ago
5Anna ate of an orange and gave the other to her brother. Which equation can be used to find the difference between the amount A
finlep [7]

Answer:

C. 5/8+3/8=8/8

Step-by-step explanation:

mark me

8 0
2 years ago
6 ÷ 1/3= what is the answer
Sav [38]
So it would be
6/2
=3 :)
6 0
4 years ago
Read 2 more answers
2w+w^3-1/2w^2 for w=2
mars1129 [50]

The required value is 8

How can we find value?

We will find the value by putting the value of w in the given function to get the required value.

We can find the value of given function foe w=2 as shown below:

Given, function is 2w+w^3-1/2w^2

Let A=2w+w^3-1/2w^2

for w=2

A=2(2)+(2)^3-1/2(2)^2

= 2+8-1/2(4)

=2+8-2

=8

Hence, the required value is 8.

Learn more about function here:

brainly.com/question/875118

#SPJ1

8 0
1 year ago
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