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Tomtit [17]
3 years ago
10

Help please?!?!?!?!?!?!?!?!?!?!?!?!

Mathematics
2 answers:
Digiron [165]3 years ago
5 0
72-[(3×2^3)+48]
72-[(3×8)+48]
72-[24+48]
72-72
0

so your answer is ZERO ( 0 )
zubka84 [21]3 years ago
3 0

PEMDAS.

Parentheses

Exponents

Multiplication

Division

Addition

Subtraction

Lets apply that here.

72-[(3x2^3)+48]

So first we start with (3x2^3)

2^3=8

3*8=24

now we do 24+48 which equals 72

now we have 72-72 which equals zero.

So

72-[(3x2^3)+48] = 0

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Question 7 A number cube with faces labeled from 1 to 6 will be rolled once. The number rolled will be recorded as the outcome.
QveST [7]

Answer:

1) S=\{1,2,3,4,5,6\}

2) O=\{1,3,5\}

Step-by-step explanation:

Given : A number cube with faces labeled from 1 to 6 will be rolled once. The number rolled will be recorded as the outcome.

To find : Give the sample space describing all possible outcomes. Then give all of the outcomes for the event of rolling an odd number. If there is more than one element in the set, separate them with commas ?

Solution :

A number cube with faces labeled from 1 to 6 will be rolled once.

The sample space describing all possible outcomes is given by

S=\{1,2,3,4,5,6\}

All of the outcomes for the event of rolling an odd number is given by

O=\{1,3,5\}

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