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baherus [9]
3 years ago
14

When the production manager finds the average life of her bulb-lifetime data, this is an example of what phase of inferential st

atistics?.
Mathematics
2 answers:
Brums [2.3K]3 years ago
7 0

Answer with explanation:

In Inferential Statistics,maximum number of times data is read to find or deduce the Correct Information about the data set ,with the help of Different Measures of variation or for the particular kind of information.And then the old  Hypothesis about the Data set is being tasted and if found incorrect, remedial measures are taken, that is  it can be altered and Correct Hypothesis is Structured.

→Data Set is about : Average life of Different Bulbs

→Measure of Variation : Mean

→Phase of inferential statistics: Data Analysis  

Data Analysis ,that is with the help of mean,average life of bulb-lifetime data is gathered.

s2008m [1.1K]3 years ago
7 0

When the production manager finds the average life of her bulb-lifetime data, she’s doing the data analysis phase of inferential statistics. I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.

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How many liters will a U.S. 6-quart container hold? Round your answer to the nearest hundredth
vovikov84 [41]
<span>You are given volume of 6 US quart. You are required to convert this into liters and be rounded off to the nearest hundredth.  Keep in mind that for volume, every one liter is equal to 1.05669 US quart. So you need to divide the 6 US quart. This is equal to 6.34014 liters. To round of the nearest hundredth, the ocation of the hundredth is the four in 6.3<u>4</u>014. since after four is zero, the round off rule states that from 0-4, the preceding number remains unchanged. So the final answer is 6.34 liters.</span>
8 0
4 years ago
Read 2 more answers
Show work and explain with formulas:
Marina86 [1]

17 Answer:  205

<u>Step-by-step explanation:</u>

\{1\dfrac{2}{3}+1\dfrac{5}{6}+2+...+8\dfrac{1}{3}\}\implies a_1=1\dfrac{2}{3},\ d=\dfrac{1}{6}\\\\\\a_n=a_1+d(n-1)\qquad solve\ for\ n\\\\8\dfrac{1}{3}=1\dfrac{2}{3}+\dfrac{1}{6}(n-1)\\\\\\\dfrac{25}{3}=\dfrac{5}{3}+\dfrac{1}{6}n-\dfrac{1}{6}\\\\\\\dfrac{50}{6}=\dfrac{10}{6}+\dfrac{1}{6}n-\dfrac{1}{6}\\\\\\\dfrac{41}{6}=\dfrac{1}{6}n\\\\\\\dfrac{41}{6}\cdot 6=n\\\\41=n

\text{Now use the sum formula:}\\\\S_n=\dfrac{a_1+a_n}{2}\cdot n\\\\\\S_{41}=\dfrac{1\dfrac{2}{3}+8\dfrac{1}{3}}{2}\cdot 41\\\\\\.\quad =\dfrac{10}{2}\cdot 41\\\\\\.\quad =5\cdot 41\\\\.\quad =\large\boxed{205}

18 Answer:  1968

<u>Step-by-step explanation:</u>

a_1=-6,\ d=2,\ n=48, \quad \text{solve for }a_{48}\\\\a_{n}=a_1+d(n-1)\\\\a_{48}=-6+2(48-1)\\\\.\quad =-6+2(47)\\\\.\quad =-6+94\\\\.\quad =88

\text{Now use the sum formula:}\\\\S_n=\dfrac{a_1+a_n}{2}\cdot n\\\\\\S_{48}=\dfrac{-6+88}{2}\cdot 48\\\\\\.\quad =\dfrac{82}{2}\cdot 48\\\\\\.\quad =41\cdot 48\\\\.\quad =\large\boxed{1968}

19 Answer:  -116

<u>Step-by-step explanation:</u>

\{3, -2, -7, ...\}\\a_1=3,\ d=-5,\ n=8, \quad \text{solve for }a_{8}\\\\a_{n}=a_1+d(n-1)\\\\a_{8}=3-5(8-1)\\\\.\quad =3-5(7)\\\\.\quad =3-35\\\\.\quad =-32\\\\\text{Now use the sum formula:}\\\\S_8=\dfrac{a_1+a_8}{2}\cdot 8\\\\\\S_{8}=\dfrac{3-32}{2}\cdot 8\\\\\\.\quad =\dfrac{-29}{2}\cdot 8\\\\\\.\quad =-29\cdot 4\\\\.\quad =\large\boxed{-116}

6 0
3 years ago
What are the values of x and y?
ss7ja [257]

Answer: x=35 and y=72.5

Step-by-step explanation:

Everything os 360, so x is 35 because it los like it has the same measure as the another 35, so if you substract 70 360=290 and 290/4 = 72.5

5 0
3 years ago
Plz I need help I really need help
Fynjy0 [20]

Answer:

-1 1/2

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Explain how you know 21/100 is greater than 1/5
Nataly_w [17]

This problem can be solved using equivalent fractions. The first step in resolving this problem is to realize that fractions are best compared when they both have the same denominator.  In this case, I will choose to make that common denominator 100. There is no need to rewrite the fraction \frac{21}{100} as the denominator for this fraction is already 100. The fraction \frac{1}{5} =\frac{20}{100} . This is achieved by multiplying both the numerator and denominator by 20. Now that the two fractions have the same denominator, we can easily see that \frac{21}{100} is greater than \frac{1}{5} because it is greater than its equivalent fraction.

5 0
3 years ago
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