Answer:
Answer: b = 58/5 or 11 3/5 or 11.6 decimal
Step-by-step explanation:
Solve for b:
b - (3 + 2/5) = 8 + 1/5
Put 3 + 2/5 over the common denominator 5. 3 + 2/5 = (5×3)/5 + 2/5:
b - (5×3)/5 + 2/5 = 8 + 1/5
5×3 = 15:
b - (15/5 + 2/5) = 8 + 1/5
15/5 + 2/5 = (15 + 2)/5:
b - (15 + 2)/5 = 8 + 1/5
15 + 2 = 17:
b - 17/5 = 8 + 1/5
Put each term in b - 17/5 over the common denominator 5: b - 17/5 = (5 b)/5 - 17/5:
(5 b)/5 - 17/5 = 8 + 1/5
(5 b)/5 - 17/5 = (5 b - 17)/5:
(5 b - 17)/5 = 8 + 1/5
Put 8 + 1/5 over the common denominator 5. 8 + 1/5 = (5×8)/5 + 1/5:
(5 b - 17)/5 = (5×8)/5 + 1/5
5×8 = 40:
(5 b - 17)/5 = 40/5 + 1/5
40/5 + 1/5 = (40 + 1)/5:
(5 b - 17)/5 = (40 + 1)/5
40 + 1 = 41:
(5 b - 17)/5 = 41/5
Multiply both sides of (5 b - 17)/5 = 41/5 by 5:
(5 b - 17)/(5 1/5) = 1/5×1/(1/5) 41
1/5×1/(1/5) = 1:
5 b - 17 = 1/5×1/(1/5) 41
1/5×1/(1/5) = 1:
5 b - 17 = 41
Add 17 to both sides:
5 b + (17 - 17) = 17 + 41
17 - 17 = 0:
5 b = 41 + 17
41 + 17 = 58:
5 b = 58
Divide both sides of 5 b = 58 by 5:
(5 b)/5 = 58/5
5/5 = 1:
Answer: b = 58/5 or 11 3/5 or 11.6 decimal
Answer:
23
Step-by-step explanation:
133 = 18 + 5x
155 = 5x
23 = x
Answer:
Step-by-step explanation:
Question
Find the perimeter of a triangle with vertices A(2,5) B(2,-2) C(5,-2). Round your answer to the nearest tenth and show your work.
perimeter of a triangle = AB+AC+BC
Using the distance formula
AB = sqrt(-2-5)²+(2-2)²
AB = sqrt(-7)²
AB =sqrt(49)
AB =7
BC = sqrt(-2+2)²+(2-5)²
BC = sqrt(0+3²)
BC =sqrt(9)
BC =3
AC= sqrt(-2-5)²+(2-5)²
AC= sqrt(-7)²+3²
AC =sqrt(49+9)
AC =sqrt58
Perimeter = 10+sqrt58
Answer:
D. 100
Step-by-step explanation:
Mean = Sum of all numbers divided by the count of all numbers
Mean = 50
Let say that the sum of all numbers = X
50 = X / 4
200 = X
X = (20+30+50) + The 4th Value
200 = 100 + 4th Value
The 4th Value = 100
Answer:
It has a minimum and no maximum.
Step-by-step explanation:
This is the graph of a parabola that opens up, so it has a minimum but no maximum.