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irina [24]
3 years ago
7

If 3 students averaged 68 on a test and 4 students averaged 75, what is the average of all 7 students

Mathematics
2 answers:
Andreas93 [3]3 years ago
8 0

Answer:  3 students

68 68 68

4 students

75 75 75 75

Answer: 71.5

insens350 [35]3 years ago
5 0

Answer:13

Step-by-step explanation:

i uave sjfjd

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Two similiar rectangles have corresponding sides in the ratio 10:3. What is the ratio of their areas
lianna [129]

Answer:

Step-by-step explanation:

The ratio of its areas is equal to

Step-by-step explanation:

we know that

If two figures are similar, then the ratio of its areas is equal to the scale factor squared

In this problem the scale factor is equal to the ratio 10:3

Let

z-------> the scale factor

so

z2=(10/3)2=100/9

7 0
3 years ago
For the following inequality, indicate whether the boundary line should be dashed or solid. x ≤ 5
lukranit [14]
Answer: The boundary lien should be solid because the inequality indicates that the value “5” is included. Remember: “greater than or equal to; less than or equal to,” as solid lines. While “<;>” are dashed lines.
6 0
4 years ago
What is the answer to 3p^4 times 5p^2
sladkih [1.3K]

Answer:

I'm pretty sure the answer is 15p^8

4 0
3 years ago
What is 1.847 and 1.798 rounded to nearest hundredth of a pound
Alisiya [41]
1.847 rounds to 1.85 because the number in the thousandths place bumps it up since it is greater then 4. 1.798 rounds to 1.8 because the number in the thousandths place bumps the nine up to ten and you can't have a two digit number where there is only supposed to be one. so that "ten" bumps the 7 up to 8.
3 0
3 years ago
Read 2 more answers
It appears that people who are mildly obese are less active than leaner people. One study looked at the average number of minute
fredd [130]

Answer:

0.0322; 0.9929

Step-by-step explanation:

Since the data is normally distributed, we use z scores for these probabilities.

The formula for a z score of a sample mean is

z=\frac{\bar{X}-\mu}{\sigma \div \sqrt{n}}

For the sample of mildly obese people, the mean, μ, is 371; the standard deviation, σ, is 65; and the sample size, n, is 6.

Using 420 for X,

z = (420-371)/(65÷√6) = 49/(65÷2.4495) = 49/26.5360 ≈ 1.85

Using a z table, we see that the area under the curve to the left of this is 0.9678.  However, we want the area to the right, so we subtract from 1:

1-0.9678 = 0.0322

For the sample of lean people, the mean, μ, is 528; the standard deviation, σ, is 108; the sample size, n, is 6.

Using 420 for X, we have

z = (420-528)/(108÷√6) = -108/(108÷2.4495) = -108/44.0906 ≈ -2.45

Using a z table, we see that the area under the curve to the left of this is 0.0071.  We want the area under the curve to the right, so we subtract from 1:

1-0.0071 = 0.9929

7 0
3 years ago
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