Answer:
segment AB over segment A double prime B double prime = the square root of 13 over 2 times the square root of 13
Step-by-step explanation:
Triangle ABC has vertices at points A(-3,3), B(1,-3) and C(-3,-3).
1. Reflection over x = 1 maps vertices A, B and C as follows
- A(-3,3)→A'(5,3);
- B(1,-3)→B'(1,3);
- C(-3,-3)→C'(5,-3).
2. Dilation by a scale factor of 2 from the origin has the rule
(x,y)→(2x,2y)
So,
- A'(5,3)→A''(10,6);
- B'(1,3)→B''(2,6);
- C'(5,-3)→C''(10,-6)
See attached diagram for details
Note that
so
Answer:
-164x^2
Step-by-step explanation:
The Perimeter of a square is 4s where s is the length of 1 side.
So P=4(-41x^2) 41*4=164 ----> P=-164x^2
Answer:
-18
Step-by-step explanation:
-15+6=-9
the absolute value of -9 is 9
and 9*-2=-18
Answer:
Step-by-step explanation:
First we'll work out the surface area of the pink figure.
That's the area of the two 5 by 6 rectangles on the top and bottom, plus the area of the two 5 by 20 and two 6 by 20 rectangles on the sides.
However, we note that the purple figure is blocking out a 6 by 12 section on the pink figure, so we'll need to subtract this.
The above works out to 
.
Then we'll work out the surface area of the purple figure.
This will be the area of the two 4 by 6 rectangles at the top and bottom, plus the area of the two 4 by 12 and one 6 by 12 rectangles on the sides. Note that there's only one 6 by 12 rectangle because the other face is joined to the pink figure, so it's blocked out.
That's 
.
So the total surface area is 
.
