First term ,a=4 , common difference =4-7=-3, n =50
sum of first 50terms= (50/2)[2×4+(50-1)(-3)]
=25×[8+49]×-3
=25×57×-3
=25× -171
= -42925
derivation of the formula for the sum of n terms
Progression, S
S=a1+a2+a3+a4+...+an
S=a1+(a1+d)+(a1+2d)+(a1+3d)+...+[a1+(n−1)d] → Equation (1)
S=an+an−1+an−2+an−3+...+a1
S=an+(an−d)+(an−2d)+(an−3d)+...+[an−(n−1)d] → Equation (2)
Add Equations (1) and (2)
2S=(a1+an)+(a1+an)+(a1+an)+(a1+an)+...+(a1+an)
2S=n(a1+an)
S=n/2(a1+an)
Substitute an = a1 + (n - 1)d to the above equation, we have
S=n/2{a1+[a1+(n−1)d]}
S=n/2[2a1+(n−1)d]
B and c, anything with an x^2 term is a quadratic.
Answer:
Alex (0.95), Tonya (0.90), Wilson (0.87), Octavia (0.80)
Step-by-step explanation:
To solve this, we have to convert all of the scores into either a decimal or a fraction. In this case, I will be solving all of them into decimals since it is easier.
Alex: 0.95
Octavia: 16/20 = 0.80
Tonya: 9/10 = 0.90
Wilson: 0.87
Therefore, we can order these from greatest score to least score.
Alex (0.95), Tonya (0.90), Wilson (0.87), Octavia (0.80)
Answer:
Es mayor
Step-by-step explanation:
Si te sirvio la respuesta por favor dame coronita y sigueme༼ つ ◕_◕ ༽つ
Perimeter of 1 tablecloth = 3+3+2+2= 10
Total fringe needed = 10x3 = 30 meters
