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3 years ago

If k is a constant, what is the value of k such that the polynomial k^2x^3 - 6kz+9 is

Mathematics

1 answer:

Tresset [83]3 years ago

3 0

$x-1$ divides $p(x)=k^2x^3-6kx+9$ if the remainder is $p(1)=0$ . (This is the remainder theorem)

Then we must have

$p(1)=k^2-6k+9=(k-3)^2=0\implies\boxed{k=3}$

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Answer:

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Step-by-step explanation:

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blsea [12.9K]

Answer:

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Step-by-step explanation:

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3 years ago

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Answer:

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Answer:

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2 years ago

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