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3 years ago

14

Solve by factoring 3x squared -5x-12=0

1 answer:

Goshia [24]3 years ago

8 0

Answer:

x = $-\frac{4}{3} , 3$

Step-by-step explanation:

We can factor $3x^{2} -5x-12$ into two factors like below. (Notice how they can't be simplified any further.)

(3x + 4) (x - 3)

Now we need to find out what value of x would satisfy the equation, or make the problem equal to 0. If we multiply $-\frac{4}{3}$ by 3, and add it to 4, then that equals 0. So, that must be one of the values of x. Next, if we replace x with 3 in the next factor, then it is 3-3, which equals 0 as well. So, that must be a solution as well.

This brings us to our solution of x = $-\frac{4}{3}$ and 3. Hope this made sense, not sure if I explained it that well.

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3 years ago

If u=0, make t the subject of the following equation: s=ut+1/2at^2 Please look at image.

Sladkaya [172]

Answer:

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Step-by-step explanation:

The given equation is :

$s=ut+\dfrac{1}{2}at^2$

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3 years ago

Drag the tiles to the boxes to form correct pairs

Brums [2.3K]

Answer:

1) $sin^{-1}(\frac{1}{\sqrt{2} })=45$

2) $cos^{-1}(\frac{\sqrt{3} }{2})=30$

3) $tan^{-1}(\sqrt{3})=60$

4) $sin^{-1}(1)=90$

Step-by-step explanation:

1) Value of $sin^{-1}(\frac{\sqrt{2} }{2}) =sin^{-1}(\frac{1}{\sqrt{2} })$

since sin45° = 1/√2

Therefore $sin^{-1}(\frac{1}{\sqrt{2} })=45$

2).Value of $cos^{-1}(\frac{\sqrt{3} }{2})$

Since cos 30° = √3/2

Therefore $cos^{-1}(\frac{\sqrt{3} }{2})=30$

3). Value of $tan^{-1}(\frac{3}{\sqrt{3} }) = tan^{-1}(\sqrt{3})=60$

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therefore $tan^{-1}(\sqrt{3})=60$

4). Value of $sin^{-1}(1)$

Since sin90°=1

Therefore $sin^{-1}(1)=90$

3 0

3 years ago

Read 2 more answers

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pashok25 [27]

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7 0

4 years ago