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aleksley [76]
3 years ago
11

A zoo has 151515 Emperor penguins. The Emperor penguins make up 30%, percent of all the penguins at the zoo.

Mathematics
2 answers:
Orlov [11]3 years ago
6 0
30% of 151515 would be 45454.5 Emperor Penguins<span />
Fed [463]3 years ago
5 0
454545.0 is the answer
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What is the length of a side of a cube with a volume of 216 in3
anyanavicka [17]
\sf volume~of~a~cube = side^3\\\\v = 216\\\\s^3 = 216\\\\s^3 = 6\times 6\times 6\\\\s^3 = 6^3\\\\\boxed{s = 6}

s = 6 in
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5 - 2 (a + 3b) / 2 = ? / ?
Semmy [17]

Answer:

(5-2a+6b)/2

Step-by-step explanation:

According to PEMDAS, we would multiply 2 by (a+3b) first. This would equal 2a+6b. Since this is being subtracted from 5, the numerator would equal 5-2a+6b. This would bring the simplified answer to (5-2a+6b)/2

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The line width used for semiconductor manufacturing is assumed to be normally distributed with a mean of 0.5 micrometer and a st
Alinara [238K]

Answer:

There is a 0.82% probability that a line width is greater than 0.62 micrometer.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by

Z = \frac{X - \mu}{\sigma}

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. The sum of the probabilities is decimal 1. So 1-pvalue is the probability that the value of the measure is larger than X.

In this problem

The line width used for semiconductor manufacturing is assumed to be normally distributed with a mean of 0.5 micrometer and a standard deviation of 0.05 micrometer, so \mu = 0.5, \sigma = 0.05.

What is the probability that a line width is greater than 0.62 micrometer?

That is P(X > 0.62)

So

Z = \frac{X - \mu}{\sigma}

Z = \frac{0.62 - 0.5}{0.05}

Z = 2.4

Z = 2.4 has a pvalue of 0.99180.

This means that P(X \leq 0.62) = 0.99180.

We also have that

P(X \leq 0.62) + P(X > 0.62) = 1

P(X > 0.62) = 1 - 0.99180 = 0.0082

There is a 0.82% probability that a line width is greater than 0.62 micrometer.

3 0
3 years ago
Find the measure of missing angle 20 130
lana [24]

Answer:

30°

Step-by-step explanation:

130+20=150

180-150= 30

6 0
3 years ago
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