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2 years ago

What is 8% as a fraction

Mathematics

2 answers:

Julli [10]2 years ago

4 0

8/100
8 over 100
%=100
so, 8/100

NemiM [27]2 years ago

4 0

8/100=2/25 because a percent is out of 100 so you take 8 and put 100 underneath it to make it a fraction and then you can simplify it

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Express answer in exact form.

Kruka [31]

We know that
<span>the regular hexagon can be divided into 6 equilateral triangles
</span>
area of one equilateral triangle=s²*√3/4
for s=3 in
area of one equilateral triangle=9*√3/4 in²

area of a circle=pi*r²

in this problem the radius is equal to the side of a regular hexagon
r=3 in
area of the circle=pi*3²-----> 9*pi in²
we divide that area into 6 equal parts------> 9*pi/6----> 3*pi/2 in²

the area of a segment formed by a side of the hexagon and the circle is equal to <span>1/6 of the area of the circle minus the area of 1 equilateral triangle
</span>so
[ (3/2)*pi in²-(9/4)*√3 in²]

the answer is
[ (3/2)*pi in²-(9/4)*√3 in²]

6 0

3 years ago

1. Find the distance between each pair of points. Round your answer to

zlopas [31]

Step-by-step explanation:

$\sqrt{(3 - ( - 4))^{2} + ( - 7 - 6)^{2} } \\ = \sqrt{(3 + 4)^{2} + {( - 13)}^{2} } \\ = \sqrt{ 49 + 169} \\ = \sqrt{218} \\ = 14.7648$

7 0

2 years ago

Solve for x by completing the square: x2 - 12x + 11 = 0

sineoko [7]

Answer:

Step-by-step explanation:

x² - 12x + 11 = 0 ( subtract 11 from both sides )

x² - 12x = - 11

To complete the square

add ( half the coefficient of the x- term )² to both sides

x² + 2(- 6)x + 36 = - 11 + 36

(x - 6)² = 25 ( take square root of both sides )

x - 6 = ± $\sqrt{25}$ = ± 5 ( add 6 to both sides )

x = 6 ± 5

Then

x = 6 - 5 = 1 ⇒ (1, 0 )

x = 6 + 5 = 11 ⇒ (11, 0 )

6 0

2 years ago

If 100 students are surveyed, about how many students own 2 or more pets? Explain. Problem: 9/20x100 Please tell me how to get t

maria [59]

Answer:

Step-by-step explanation:

20 goes into 100 5 times so then you tka e the 9 and x 5 and you get 45

8 0

2 years ago

Insurance companies are interested in knowing the population percent of drivers who always buckle up before riding in a car. The

Tems11 [23]

Answer:

The 84% confidence interval for the population proportion that claim to always buckle up is (0.74, 0.80).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the z-score that has a p-value of $1 - \frac{\alpha}{2}$ .

They randomly survey 387 drivers and find that 298 claim to always buckle up.

This means that $n = 387, \pi = \frac{298}{387} = 0.77$

84% confidence level

So $\alpha = 0.16$ , z is the value of Z that has a p-value of $1 - \frac{0.16}{2} = 0.92$ , so $Z = 1.405$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.77 - 1.405\sqrt{\frac{0.77*0.23}{387}} = 0.74$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.77 + 1.405\sqrt{\frac{0.77*0.23}{387}} = 0.8$

The 84% confidence interval for the population proportion that claim to always buckle up is (0.74, 0.80).

6 0

2 years ago