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Blababa [14]
3 years ago
7

What are t + 8 + 3t terms and like

Mathematics
1 answer:
Bond [772]3 years ago
3 0

Answer:

t+8+3t

8+4t

Step-by-step explanation:

I guess the question is incomplete

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Please help asap!!! I’ll give you a thank you
stich3 [128]

Answer:

V≈536.38

Step-by-step explanation:

V=a3

7 0
4 years ago
Melissa buys 2 1/2 pounds of salmon an 1 1/4 pounds of swordfish. She pays a total of $31.25, and the swordfish costs $0.20 per
garik1379 [7]

Answer:

$16.60

Step-by-step explanation:

Setup the formula to calculate the cost of each pound of salmon and swordfish for the 2.5 pounds of salmon (x) and 1.25 pounds of swordfish (y) which is equal to $31.25

2.5x + 1.25y = 31.25

Setup a formula to figure out how much a single pound of swordfish (y) is. The problem states it cost $0.20 less than a pound of salmon (x).

y = x - .20

Plug the y = x - .20 into the first equation.

2.5x + 1.25(x - .20) = 31.25

Distribute the 1.25 by multiplying it with x and -.20

2.5x + 1.25x - .25 = 31.25

Combine like terms, x on the left side

3.75x - .25 = 31.25

Add .25 to both sides to get x on one side

3.75x = 31.50

Divide both sides by 3.75 to get x by itself

x = 8.4

So, each pound of salmon, x, cost $8.40 per pound

Use y = x - .20 and plug in x = 8.4 to figure out how much a pound of swordfish cost.

y = 8.4 - .20

So, a pound of swordfish cost $8.20 per pound

The question wants to know the combined cost, z, of 1 pound of salmon, x, and 1 pound of swordfish, y.

x + y = z

8.4 + 8.2 = 16.6

The combined cost of 1 pound of salmon and 1 pound of swordfish is $16.60

8 0
1 year ago
F(x)= x2 + 6x - 40<br><br> find f (5)<br><br> 1. 15<br> 2. 20<br> 3. 10 <br> 4. 16
Charra [1.4K]
The answer is F equals 20
7 0
3 years ago
Solve for x <br><br> (5x-1) 8x
Ghella [55]
90 + (5x-1) + 8x = 180
90 + 5x - 1 + 8x = 180
89 + 5x + 8x = 180
89 + 13x = 180
13x = 91
x = 7
5 0
3 years ago
Solve and justify each step<br> SHOW WORK<br><br> Solve: -4(n+5)&gt;3n+8
natulia [17]
-4n-20>3n+8

-7n-20>8

-7n<28
n<-4
7 0
4 years ago
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