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r-ruslan [8.4K]

3 years ago

15

What is 25 over 80 written as a decimal

1 answer:

hram777 [196]3 years ago

6 0

.3125 is equal to 25/80

You might be interested in

Can a triangle be drawn with side lengths 8.4 inches, 9.2 inches, and 17 inches?

sasho [114]

Answer:

yes

Step-by-step explanation:

based on the triangle inequality theorem, add the two smallest numbers together (8.4,9.2) to get 17.6 which is bigger than 17

3 0

3 years ago

Which of the triangles shown are right triangles?

d1i1m1o1n [39]

The right angle triangles are:

Triangle A has two acute angles and one ninety degree angle

Triangle d has two acute angles and one ninety degree angle.

<h3>What are right triangles?</h3>

A triangle is a three-sided polygon with three edges and three vertices. the sum of angles in a triangle is 180 degrees. A right angled triangle is a triangle in which one of its angles measure 90 degrees.

To learn more about triangles, please check: brainly.com/question/22949981

#SPJ1

6 0

2 years ago

Subtract 28.9 − 9.25 =_____

yaroslaw [1]

19.65 hope this helps :)

8 0

3 years ago

Read 2 more answers

19. Use the unit circle to find the value of tan 315º.<br> Show work pls.

Free_Kalibri [48]

Answer: -1

Step-by-step explanation:

First change tan(315) to:

$\frac{\sin(315)}{\cos(315)}$

Then evaluate the sine and cosine function. What is the y component of 315 degrees? What is the x component of 315 degrees?

$-\frac{\sqrt{2} }{2} /\frac{\sqrt{2} }{2} =-1$

7 0

3 years ago

Write a solution in Interval Notation - (you don't have to help me on all, 1 or 2 is fine c: )

Gemiola [76]

QUESTION 1

The given inequality is

$|m|-2>0$

We group like terms to get,

$|m|>2$

This implies that,

$-m>2$ or $m>2$ .

We simplify the inequality to get,

$m$ or $m>2$ .

We can write this interval notation to get,

$(-\infty,-2)\cup (2,+\infty)$ .

QUESTION 2

$|x-4|-3\:>\:5$ .

We group like terms to get,

$|x-4|\:>\:5+3$ .

$|x-4|\:>\:8$

We split the absolute value sign to get,

$-(x-4)\:>\:8$ or $x-4\:>\:8$

This implies that,

$x-4\:$ or $x-4\:>\:8$

$x\:$ or $x\:>\:8+4$

$x\:$ or $x\:>\:12$

We can write this interval notation to get,

$(-\infty,-4)\cup (12,+\infty)$ .

QUESTION 3

The given inequality is

$|6+9x|\leq 24$

We split the absolute value sign to obtain,

$-(6+9x)\leq 24$ or $(6+9x)\leq 24$

This simplifies to

$6+9x\ge -24$ and $6+9x\leq 24$

$9x\ge -24-6$ and $9x\leq 24-6$

$9x\ge -30$ and $9x\leq 18$

$x\ge -\frac{10}{3}$ and $x\leq 2$

$-\frac{10}{3}\leq x\leq2$

We write this in interval form to get,

$[-\frac{10}{3},2]$

QUESTION 4

The given inequality is

$|1-5a|>29$

We split the absolute value sign to get,

$-(1-5a)>29$ or $1-5a>29$

This simplifies to,

$1-5a\:$ or $1-5a\:>\:29$

This implies that,

$-5a\:$ or $-5a\:>\:29-1$

$-5a\:$ or $-5a\:>\:28$

$a\:>\:6$ or $a\:$

We write this in interval notation to get,

$(-\infty,-\frac{28}{5})\cup (6,+\infty)$

7 0

3 years ago