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Thepotemich [5.8K]
3 years ago
15

___is a comparison of two quantities by division

Mathematics
1 answer:
pashok25 [27]3 years ago
7 0

Answer: a ratio

Step-by-step explanation:

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Select the correct answer.
aleksandrvk [35]
I think it should be b
3 0
4 years ago
Suppose you are conducting a study to compare firefly populations exposed to normal daylight/darkness conditions with firefly po
HACTEHA [7]

Answer:

a) This is an experiment, since one of the variables is being controlled. The<u> light exposure is set to work 24h a day, this is done because the researcher has made a choice</u>. In an observational study, the researcher has no control over the variables, so no changes happen with the sample groups. Some notes are taken about their behavior, but there isn't any element that is being manipulated.

b) The control group is the one in which the fireflies keep their usual routine, there aren't any changes in their environment. This is the population exposed to normal daylight/darkness. The treatment group is the one in which the fireflies live under different conditions from what they are used to, being this the ones that are exposed to continuous light 24h/day.

c) The variable of interest in this study is the rate of survival after continuous light exposure compared to natural light exposure. The level of measurement used is ratio scale, then, since the question being made with this research is "how many individuals are going to survive?". Ratio scales allow reserachers to count concrete data.

3 0
3 years ago
Which expressions are equivalent to 42-5? Choose all the correct answers. Show your work in arriving at your answers.
frozen [14]

Answer:

B, C, E

Step-by-step explanation:

<u />

<u>Exponent Rules</u>

a^b \cdot a^c=a^{b+c}

\dfrac{a^b}{a^c}=a^{b-c}

a^n \cdot b^n=(ab)^n

a^0=1

\dfrac{1}{a^b}=a^{-b}

(a^b)^c=a^{bc}

\textsf{A}\quad42^{-3} \cdot 42^8=42^{-3+8}=42^5

\textsf{B}\quad \dfrac{42^{-7}}{42^{-2}}=42^{-7-(-2)}=42^{-5}

\textsf{C}\quad \dfrac{6^{-5}}{7^5}=6^{-5} \cdot 7^{-5}=(6 \cdot 7)^{-5}=42^{-5}

\textsf{D}\quad 42^0 \cdot 42^5=1 \cdot 42^5=42^5

\textsf{E}\quad \left(\dfrac{1}{42^{-5}}\right)^{-1}=(42^5)^{-1}=42^{-5}

\textsf{F}\quad \left(\dfrac{6^{-5}}{7^5}\right)^{-1}=\left(6^{-5} \cdot 7^{-5}\right)^{-1}=\left(\left(6 \cdot 7\right)^{-5}\right)^{-1}=42^{-5(-1)}=42^5

3 0
2 years ago
Read 2 more answers
How to factor 3n^2-17n+24
MariettaO [177]
Find the factors of 3, which are 1, 3 or -1, -3,  and 24, which can be 1,24; 2,12; 3, 8; 4, 6,  negative and positive, and write them this way: factors of 3 to the left, factors of 24 to the right.
then multiply diagonally and add up the products. Keep trying different pairs of factors till you make a -17

1     -3

3     -8

 1*(-8) + 3(-3) = -17
so (n-3)(3n-8) is the factored form of the expression
5 0
3 years ago
The graph of y=f(x) is shown below. According to the graph, what is f(0)?
stepladder [879]

from,

y = f(x)

then,

f(0)

this means that x = 0

from the graph x = 0 is found at C

y = -2.

All the best!

5 0
3 years ago
Read 2 more answers
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