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3 years ago

Please help me answer this multiple choice question please

Mathematics

1 answer:

drek231 [11]3 years ago

5 0

Answer:

Step-by-step explanation:

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For the function f(x)=3(x-1)^2+2, identify the vertex,domain, and range -The vertex is (1,2), the domain is all real numbers, an

sdas [7]

Answer:

The function is...f(x)=(-1,-2)

Step-by-step explanation:

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3 years ago

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Find, if it exists, a value c in the interval [1, 4] such that the instantaneous rate of change of f(x) = 12<img src="https://te

ella [17]

Answer:

c = 2.25

Step-by-step explanation:

f(x) is a continuous and differentiable function on the interval, so the Mean Value Theorem guarantees a value for c exists.

The average slope is ...

m = (f(4) -f(1))/(4 -1) = (24 -12)/3 = 4

The point at which the derivative is 4 is ...

f'(c) = 6/√c = 4

√c = 6/4

c = 2.25

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3 years ago

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Brainliest to correct answer

aksik [14]

Answer:

No, zack will finish first.

Step-by-step explanation:

I would rather not write it out but zack should finish first

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3 years ago

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If the substitution u=x/2 is made, the intergal from 2 to 4 1-(x/2)^2/x dx =

stich3 [128]

$\displaystyle\int_2^4\frac{1-\left(\frac x2\right)^2}x\,\mathrm dx$

Setting $u=\dfrac x2$ gives $\mathrm du=\dfrac{\mathrm dx}2$ , or $2\,\mathrm du=\mathrm dx$ . This also makes $2u=x$ .

When $x\to2^+$ , you have $u\to\dfrac22=1$ , while when $x\to4^-$ , you have $u\to\dfrac42=2$ .

Putting everything together, you find that

$\displaystyle\int_2^4\frac{1-\left(\frac x2\right)^2}x\,\mathrm dx=\int_1^2\frac{1-u^2}{2u}(2\,\mathrm du)=\int_1^2\frac{1-u^2}u\,\mathrm du$

which means (B) is the correct answer.

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3 years ago

Solve these word problems:

mina [271]

Answer:

45 cats prefer fish

Step-by-step explanation:

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3 years ago