Question

Identify all factors of the expression 18x^2-9x-5

Answer 1

factors of  $f(x) = 18x^2-9x-5$  are $3x+1$ and $6x-5$ .

Step-by-step explanation:

Here we have , to identify all factors of this expression . let's find out :

Expression : $f(x) = 18x^2-9x-5$

⇒ $f(x) = 18x^2-9x-5$

Now , -9x can be written as :

⇒ $-9x=-15x+6x$

Putting this value

⇒ $f(x) = 18x^2-15x+6x-5$

Taking out common terms we get

⇒ $f(x) = 3x(6x-5)+6x-5$

⇒ $f(x) = 3x(6x-5)+1(6x-5)$

⇒ $f(x) = (3x+1)(6x-5)$

Therefore , factors of  $f(x) = 18x^2-9x-5$  are $3x+1$ and $6x-5$ .