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AURORKA [14]
4 years ago
7

Need help with this question

Mathematics
1 answer:
Olin [163]4 years ago
4 0
To find the answer,we can use the two-point formula:
(y1 - y2) = m(x1 - x2)
Where m is the slope.

To find y,we have to first find the slope,then insert either of the coordinates into the equation.

The formula of the slope:

\frac{y1 - y2}{x1 - x2}

In this case:

\frac{6 - ( - 2)}{ - 4 - ( - 8)} \\ = \frac{6 + 2}{ - 4 + 8} \\ \frac{8}{4} \\ = 2

We can then put (-4,6) into the equation:

6-y = 2[x-(-4)]
-y = 2x+4(2)-6
-y = 2x+2
y = -(2x+2)
y = -2x-2

Therefore the answer is -2x-2.

Hope it helps!
You might be interested in
What point would be reflected across the y-axis to ( − 3, − 9) ?
Aloiza [94]

Answer:

(-3, 9)

Step-by-step explanation:

If a point was reflected across the y-axis, then the y-coordinate would change signs (from negative to positive or from positive to negative). Using this, we could find the original point by changing the sign of the y-coordinate. As you may already see, this is really just reflecting the point across the y-axis again. By doing this, you get the point (-3, 9).

The point would be (-3, 9).

I hope this helps. :)

5 0
3 years ago
Given that,
r-ruslan [8.4K]

Answer:

1

Step-by-step explanation:

1

3 0
3 years ago
What's the answer please
worty [1.4K]
12^2 - 11^2
= 144 - 121 
= 23

square root (23) = 4.79 = 4.8

answer
C. 4.8
7 0
3 years ago
Given f(x)= 3x+(1/4), Find f(1) and f(-1)
Pachacha [2.7K]

Answer:

f(1)=\frac{13}{4}

f(-1) = -\frac{11}{4}

Step-by-step explanation:

Given f(x) = 3x + (1/4),     Find f(1) and f(-1)

f(x) = 3x + (1/4)

f(1) = 3(1) + (1/4)

f(1) = 3 + (1/4)

f(1) = 3 + (1/4)

f(1)=3\frac{1}{4}

f(1)=\frac{13}{4}

f(x) = 3x + (1/4)

f(-1) = 3(-1) + (1/4)

f(-1) = -3 + (1/4)

f(-1) = -\frac{12}{4} +\frac{1}{4}

f(-1) = -\frac{11}{4}

Hope this helps!

6 0
3 years ago
If x is a number that is 7 more than y, how do you express x as a function of y?
dolphi86 [110]
The correct answers would be the first and fourth options. You’re welcome!
4 0
3 years ago
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