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stiv31 [10]
3 years ago
10

Find the area 20 points!!!

Mathematics
2 answers:
Mekhanik [1.2K]3 years ago
7 0

Answer: 29in^2

Step-by-step explanation:

The figure is formed by a square, a parallelogram and a rectangle.

Then, the area of the figure will be the sum of the area of the square, the area of the parallelogram and the area of the rectangle.

The area of the square is:

Area_1=side^2=(2in)^2=4in^2

The area of the parallelogram is:

Area_2=base*height=(5in)(3in)=15in^2

The area of the rectangle is:

Area_3=length*width=(5in)(2in)=10in^2

Therefore, the area of the figure is:

Area_T=A_1+A_2+A_3\\Area_T=4in^2+15in^2+10in^2\\Area_T=29in^2

Dmitriy789 [7]3 years ago
5 0

Answer:

the answer would be 29 :)

Step-by-step explanation:

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So,some please help me with this question !
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\qquad \qquad  \bf \huge\star \:  \:  \large{  \underline{Answer} }  \huge \:  \: \star

\qquad❖ \:  \sf   \: \angle C  = 63 \degree

\textsf{  \underline{\underline{Steps to solve the problem} }:}

\qquad❖ \:  \sf \:x + 4x  + 12 + x=180°

( Angle EBA= Angle DBC, and the three angles sum upto 180° due to linear pair property )

\qquad❖ \:  \sf \:6x + 12 = 180

\qquad❖ \:  \sf \:6x = 180 - 12

\qquad❖ \:  \sf \:6x = 168

\qquad❖ \:  \sf \:x = 28 \degree

Next,

\qquad❖ \:  \sf   \: \angle C + \angle D + x = 180°

\qquad❖ \:  \sf   \: \angle C +3x + 5  + x = 180°

\qquad❖ \:  \sf   \: \angle C +4x  = 180 - 5

\qquad❖ \:  \sf   \: \angle C +4(28)  = 175

( x = 28° )

\qquad❖ \:  \sf   \: \angle C +112  = 175

\qquad❖ \:  \sf   \: \angle C  = 175 - 112

\qquad❖ \:  \sf   \: \angle C  = 63 \degree

\qquad \large \sf {Conclusion}  :

\qquad❖ \:  \sf   \: \angle C  = 63 \degree

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