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3 years ago

11

3(7 + x) verbal expression

1 answer:

Basile [38]3 years ago

4 0

Answer:

21+3x

Step-by-step explanation:

multiply the 3 by everything inside the parentheses

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W is the midpoint of VX and Z is the midpoint of VY . If XY=p and WZ=p–30, what is WZ?

juin [17]

$\large{ \tt{❃ \: EXPLANATION}} :$

You'll have to know : Mid-point theorem states that A straight line segment joining the mid-points of any two triangle is parallel to the third side and it is equal to half of the length of the third side.

We're provided : XY = p , WZ = p - 30 & we're asked to find out the value of WZ. For that , firstly we have to find out the value of p.

$\large{ \tt{❁ \: LET'S \: START }: }$

Set up an equation & solve for p :

$\large{ \bf{☄ \: p - 30 = \frac{1}{2} p }}$

$\large{ \tt{↦ \frac{1}{2} p = p - 30}}$

$\large{ \tt{↦ \frac{1}{2} p - p = - 30}}$

$\large{ \tt{↦ \frac{p - 2p}{2} = - 30 }}$

$\large{ \tt{↦p - 2p = - 60}}$

$\large{ \tt{ ↦ \: - p = - 60}}$

$\large{ \tt{↦p = 60}}$

The value of p is 60

$\large{ \tt{❇ \: REPLACING \: VALUE}} :$

$\large{ \tt{↬ \: wz = p - 30 = 60 - 30 = \boxed{\boxed{ \tt{30 }} }✔}}$

Hence , WZ = 30 .

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7 0

3 years ago

Chicken eggs can be categorized as large if they weigh at least 2 ounces. Clare weighs 48 large eggs and finds that they have a

34kurt

Answer: The average difference of weights of all 48 eggs from mean eight is 0.08.

Step-by-step explanation:

The mean absolute deviation of a data interprets the mean distance between each data point and the mean.

When this distance goes larger it means data has greater variability

Given, 48 large eggs have a mean weight of 2.1 ounces and a mean absolute deviation of 0.08 ounces.

It means that the average difference of weights of all 48 eggs from mean eight is 0.08.

8 0

3 years ago

In Kayla's grade, 3/4 of the students have a sister. Of the students who have a sister, 2/5

ioda

Answer:brother? Simplify your answer and write it as a fraction or as a whole or mixed number.

Step-by-step explanation:

4 0

2 years ago

Can someone figure this out

maria [59]

Answer:

Option C

Step-by-step explanation:

Option C is correct one

y= -2x+1, x>1

y= -x+2, x≤1

5 0

3 years ago

Use Newton's method to find the second and third approximation of a root of x3+x+2=0 starting with x1=−1 as the initial approxim

adoni [48]

Answer:

The third approximation is $x_3=-1.08259$

Step-by-step explanation:

We are given that

$f(x)=x^3+x+2=0$

$x_1=-2$

We have to find the second and third approximation of a root of given equation by using Newton's method.

We know that Newton's method , if nth approximation is given $x_n$ and $f'(x_n)\neq 0$ then, the next approximation is given by

$x_{n+1}=x_n-\frac{f(x_n)}{f'(x_n)}$

$f'(x)=3x^2+1$

Substitute $x_1=-2$

$f(x_1)=f(-2)=(-2)^3+(-2)+2=-8$

$f'(x_1)=f'(-2)=3(-2)^2+1=13$

Substitute the value n=1 then, we get

$x_2=x_1-\frac{f(x_1)}{f'(x_1)}$

Substitute the values then , we get the second approximation

$x_2=-2-\frac{-8}{13}=-\frac{18}{13}$

For n=2

$f(x_2)=f(-\frac{18}{13})=(-\frac{18}{13})^3-\frac{18}{13}+2=-2.03914$

$f'(x_2)=f'(-\frac{18}{13})=3(-\frac{18}{13})^2+1=6.75148$

$x_3=x_2-\frac{f(x_2)}{f'(x_2)}$

$x_3=-\frac{18}{13}-\frac{-2.03914}{6.75148}=-1.08259$

Hence, the third approximation is $x_3=-1.08259$

7 0

3 years ago