If xy=0 we assume x and y equal 0
so
the zeros are wehre f(x)=0
0=5(2x-5)(5x+4)
set each to zero
5 is not equal 0 so we don't do that
0=2x-5
5=2x
5/2=x
0=5x+4
-4=5x
-4/5=x
zeroes at x=5/2 and -4/5
I think the two numbers are four and three. Hope this helps.
Answer:

Step-by-step explanation:
An apothem is a perpendicular drawn from the centre of the triangle to one of its sides.
The three apothems OD, OE, and OF divide ∆ABC into six smaller congruent triangles.
1. Area of ∆OCD
CotOCD = OD/OC
cot30 = CD/6
√3 = CD/6
CD = 6√3
A= ½bh
A = ½ × 6√3 × 6 = 18√3 in²
2. Area of ∆ABC
A = 6 × area of ∆OCD = 6 × 18√3 = 108√3 in²
