Answer:
500
Step-by-step explanation:
:D
(a) someone over 55
mean, mu = 22
standard deviation, sigma = 2
X=19
Z(X)=(X-mu)/sigma=(19-22)/2=-1.5
P(x>X)=1-P(x<X)=1-0.0668072=0.9331928
Therefore probability for a 55-year old to find a job in over 19 weeks is 0.9332
The answer is x=4.5 because 9÷2=4.5 and 4.5×2=9
This is easy he bout 40 boxes... drops mic
