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kakasveta [241]
3 years ago
12

Worth 20 points try to answer as many as possible

Mathematics
1 answer:
mojhsa [17]3 years ago
5 0
1. y=k/x (k being a constant)

40= k/16    
k= 640

so... -5= 640/x     x=-128

2. y=kx (k being a constant)

15= -18k
k=-15/18

so... y= (-15/18)(1.6)= -4/3

3. y=kx

If you're talking about as x decreases, what happens to y, then the answer would be that y decreases as well. You can plug in any amounts to prove this. The answer is the same vice versa.

4. y=kx

The value of x increases when the value of y increases. 
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What is negative 5 5/6–2 3/5
dangina [55]

Answer:

the answer is -8 13/30

Step-by-step explanation:

4 0
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HELP HELP HELP WILL GIVE BRAINLIEST
EastWind [94]

Answer:

Put one of the dots on (0, -3) and put the other one 3 below and 2 to the right of (0, -3)

Step-by-step explanation:

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3 years ago
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Tanx-cotx / sinxcosx =sec^2-csc^2x. Please show all steps. 
Katarina [22]
\bf \cfrac{tan(x)-cot(x)}{sin(x)cos(x)}\implies \cfrac{\frac{sin(x)}{cos(x)}-\frac{cos(x)}{sin(x)}}{sin(x)cos(x)}\implies \cfrac{\frac{sin^2(x)-cos^2(x)}{cos(x)sin(x)}}{\frac{sin(x)cos(x)}{1}}
\\\\\\
\cfrac{sin^2(x)-cos^2(x)}{cos(x)sin(x)}\cdot \cfrac{1}{sin(x)cos(x)}\implies \cfrac{sin^2(x)-cos^2(x)}{cos^2(x)sin^2(x)}
\\\\\\
\textit{and now, we distribute the denominator}
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\cfrac{sin^2(x)}{cos^2(x)sin^2(x)}-\cfrac{cos^2(x)}{cos^2(x)sin^2(x)}\implies 
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3 0
3 years ago
PLZ HELP I NEED BY 2:00 PM ATY LEAST!!! WILL GIVE BRAINLYIST<br> Find the value of in each case:
Pie

Answer:

23°

Step-by-step explanation:

Step 1:

< GEC + < ECG + < CGE = Δ ECG    Sum of a Δ

Step 2:

< IGF = < GCE    Corresponding ∠ 's

Step 3:

14° + 180° - 4x + 78° = 180°   Substitution

Step 4:

272° - 4x = 180°     Add / Algebra

Step 5:

- 4x = - 92   Subtract 272° on both sides

Step 6:

- 92 ÷ - 4   Divide

Answer:

x = 23°

Hope This Helps :)

7 0
3 years ago
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Business is projected to be booming afterthe latest release of The Fast and theFurious 3.14159265359... Carver's AutoCustom must
Rus_ich [418]
\begin{gathered} \text{ warehouse has 8000 sq ft, half of which is usable for stocking} \\ \text{this gives us  4000 sq ft} \\ \text{ it has a height of 20 ft, which gives us} \\ (4000ft^2)(20ft)=80000ft^3\text{ of volume} \\ \text{ The volume of the box is } \\ (36in)(36in)(15in)=19440in^3 \\ \text{ Convert it cubic inches to cubic foot} \\ 19440in^3\cdot(\frac{1ft}{12in})^3=11.25ft^3 \\ \text{ Divide the working volume of the warehouse by the volume of the box} \\ \frac{80000ft^3}{11.25ft^3}=7111.1111 \\ \text{Round it off to a whole number} \\ 7111 \\ \text{ Therefore, we can have a maximum of 7111 box of rims that we can stock} \\ \text{ in the warehouse} \end{gathered}

6 0
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