Eight more than four times a number is -12 eauation

How to do this?? give me a solution its confusing me?!!

Alika [10]

Answer:

t = 3h

Step-by-step explanation:

Given

h = $\frac{1}{3}$ t

Multiply both sides by 3 to clear the fraction

3h = t

5 0

4 years ago

Find the volume of the wedge-shaped region (Figure 1) contained in the cylinder x2+y2=81 and bounded above by the plane z=x and

Natali5045456 [20]

In cylindrical coordinates, the volume is given with

$\displaystyle\int_{\theta=-\pi/2}^{\theta=\pi/2}\int_{r=0}^{r=9}\int_{z=0}^{z=r\cos\theta}r\,\mathrm dz\,\mathrm dr\,\mathrm d\theta$
$=\displaystyle\int_{\theta=-\pi/2}^{\theta=\pi/2}\int_{r=0}^{r=9}r^2\cos\theta\,\mathrm dr\,\mathrm d\theta$
$=\displaystyle\left(\int_{\theta=-\pi/2}^{\theta=\pi/2}\cos\theta\,\mathrm d\theta\right)\left(\int_{r=0}^{r=9}r^2\,\mathrm dr\right)$
$=486$

7 0

3 years ago

Read 2 more answers

A: 2x + 8y = 5 B: x + 9y = 10 To solve this system of equations by elimination, what could you multiply equation B by if you wan

Valentin [98]

Answer :A)-2

Step-by-step explanation: If you multiply B; x + 9y =10 by -2 you will have -2 x+ -18y= -20. Then when you add B with a 2x + 8y = 5

-2x +-18y=-20

=0 +-10y=-15

5 0

3 years ago

Please help me.<br> how many observations are in this data set?

Ivenika [448]

Answer:

16

Step-by-step explanation:

count the dots. each is one observation

4 0

3 years ago

Read 2 more answers

(a) A parachutist lands at a point on the line between the points A and B, and the target is an operation at A. The operation fa

mr Goodwill [35]

Answer:

a) $\frac{B-\frac{A+5B}{6}}{B-A}= \frac{6B -A-5B}{6(B-A)}=\frac{B-A}{6(B-A)}=\frac{1}{6}$

b) $P(X>1) = 1-P(X\leq 1)=1-\int_{0}^1 \frac{1^{2} x^{2-1} e^{- x}}{\gamma(2)}=0.736$

Step-by-step explanation:

Part a

We assume that the parachutist lands at random point in the interval (x=A,y=B) we have a continuous random variable X. And the distribution of X would be uniform $Y\sim Unif(A,B)$ . And the density function would be given by:

$f(x) =\frac{1}{B-A} , A$

And 0 for other case.

The operation fails, if parachutist's distance to A is more than five times as much as her distance to B.

So the point P in the interval (A,B) at which the distance to A is exactly 5 times the distance to B is given by:

$P= A + \frac{5}{6} (B-A)= \frac{6A +5B -5A}{6}=\frac{A+5B}{6}$

And we can find the probability desired like this:

$P(d(P,A) \geq 5 d(P,B))= P(\frac{A+5B}{6} < X< B)$

And from the cumulative distribution function of X ficen by $F(X)\frac{X-A}{B-A}$ we got:

$\frac{B-\frac{A+5B}{6}}{B-A}= \frac{6B -A-5B}{6(B-A)}=\frac{B-A}{6(B-A)}=\frac{1}{6}$

Part b

For this case we assume that $X\sim Gamma (2,1)$

On this case we assume that $\alpha=2, \beta= 1$

The density function for the Gamma distribution is given by:

$P(X)= \frac{\beta^{\alpha} x^{\alpha-1} e^{-\beta x}}{\gamma(\alpha)}$

And on this case we can find the probability using the complement rule like this:

$P(X>1) = 1-P(X\leq 1)=0.736$

We can solve this problem with the following excel code:

"=1-GAMMA.DIST(1;2;1;TRUE)"

And if we do it by hand we need to do this:

$P(X>1) = 1-P(X\leq 1)=1-\int_{0}^1 \frac{1^{2} x^{2-1} e^{- x}}{\gamma(2)}=0.736$

6 0

3 years ago