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Alik [6]
3 years ago
7

What are these types of questions called

SAT
2 answers:
Hunter-Best [27]3 years ago
8 0
The questions are called prevent of change
Molodets [167]3 years ago
7 0
We just call those percent of change
You might be interested in
Which expression is equivalent to sqrt 2x^5/18 assume.
Natasha2012 [34]

Answer:

(x^2 * sq rt x)/3

Explanation:

first, simplify the 2x^5/18

you get x^5/9

square rooting 9 gives you 3

square rooting x^5 gives you x^2 * sqrt x

just put 3 in the denominator and x^2 * sq rt x in the numerator

ANSWER: (x^2 * sq rt x)/3

7 0
2 years ago
A study of the amount of time it takes a mechanic to rebuild the transmission for a 2010 Chevrolet Colorado shows that the mean
Basile [38]

Answer:

The answer is 0.9599.

Explanation:

mu (sample) = mu = 8.4

s.d. (sample) = 1.8/ sq. rt. 40

P( greater than 8.1) = (8.9-8.4)/(1.8/ sq. rt. 40)

Let x be the mean time for the 40 mechanics

Standardize the mechanics: (8.9-8.4)/(1.8/ sq. rt. 40) = 1.75 = Z

P( x > 8.9) = P(Z > 1.75), this means the area to the right of Z = 1.75.

Then you need to look in the table of the Normal distribution, Z(1.75) =0.9599

8 0
3 years ago
Read 2 more answers
Please tell me how to get the answer
jasenka [17]
D
Because if x=8 and y=3 then 3x and 8y are equal. So if we are trying to find an equal to 40y then you need to find what 40 times y equals first. So, 40x3=120. If we substitute x with 8 and multiply it with 15 then you get 120 so it’s equal.
7 0
3 years ago
A probe orbiting Venus exerts a gravitational force of 2. 58 × 103 N on Venus. Venus has a mass of 4. 87 × 1024 kg. The mass of
andriy [413]

Answer:

9.08

Explanation:

To solve for the distance between the probe and  the center of Venus, use the formula:

\mathrm{F = \frac{G\: m1 \:m2}{r^2}}

 

<u>Plugin the values</u>:

G =

6.67\times10^{-11} \mathrm{\frac{m3}{kg\: s2}}

\mathrm{F} =2.58 \times 10^3\mathrm{N}

\mathrm{m1 = 4.87 \times 10^{24}\:kg}

\mathrm{m2 = 655\: kg}

Hence:

\mathrm{F = \frac{G\: m1 \:m2}{r^2}}

2.58  \times 10^{23} = 6.67 \times 10^{-11} (4.87 \times 10^{24})

\frac{(655)}{r^2}

\mathrm{r = 9.08 \times 10^6 \:km}

4 0
3 years ago
How does the troposphere differ from the stratosphere?
aksik [14]

Hi Daralava,

How does the troposphere differ from the stratosphere?

There are 2 major difference between the troposphere and the stratosphere, which is that the stratosphere is higher located than the troposphere, also the stratosphere is also warmer becase it receives more solar radiation the the troposphere.

4 0
4 years ago
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