There are 2 way to solve this.
one using Pythagoras theorem and 2nd using trigonometry
so lets solve it by both
using Pythagoras theorem we know
base^2 + perpendicular^2 = hypotanes^2
6^2 + x^2 = 12^2
36 + x^2 = 144
x^2 = 144- 36 = 108
x = √(108) = √( 2×2×3×3×3)
= (2×3) √ (3) = 6 √3
so answer is option 2
bow lets use trigonometry
we know
sin theta = perpendicular / hypotanes
sin 60 = x /12
x = 12 × sin 60
we kNow sin 60 = √3/ 2
so
x = 12×√3 /2 = 6√3
The answer is 12 5/18 hope it helps
Aos= -b/2a so plunin your numbers and you'll get the AOS so you can find the vertex
Answer:
130
Step-by-step explanation:
2(4x - 3) + 6(3y - 5)
2(4 × 5 - 3) + 6(3 × 7 - 5)
2(20 - 3) + 6(21 - 5)
2(17) + 6(16)
34 + 96
130
Answer with Step-by-step explanation:
Suppose that a matrix has two inverses B and C
It is given that AB=I and AC=I
We have to prove that Inverse of matrix is unique
It means B=C
We know that
B=BI where I is identity matrix of any order in which number of rows is equal to number of columns of matrix B.
B=B(AC)
B=(BA)C
Using associative property of matrix
A (BC)=(AB)C
B=IC
Using BA=I
We know that C=IC
Therefore, B=C
Hence, Matrix A has unique inverse .