Given that ∠B ≅ ∠C.
to prove that the sides AB = AC
This can be done by the method of contradiction.
If possible let AB
=AC
Then either AB>AC or AB<AC
Case i: If AB>AC, then by triangle axiom, Angle C > angle B.
But since angle C = angle B, we get AB cannot be greater than AC
Case ii: If AB<AC, then by triangle axiom, Angle C < angle B.
But since angle C = angle B, we get AB cannot be less than AC
Conclusion:
Since AB cannot be greater than AC nor less than AC, we have only one possibility. that is AB =AC
Hence if angle B = angle C it follows that
AB = AC, and AB ≅ AC.
the angles the top part that has a square is 90⁰ and x and y are equal so we will name them both x and all angles together make 180⁰
I don't know about the sides
Step-by-step explanation:
90+x+x=180
2x=180-90
2x=90
x=90/2
x=45
Answer:
1. 100 1. 150 1. 1
2.45 2. 800
Step-by-step explanation:
1. 25% * 400 = 0.25 * 400 =
* 400 = 100
2. 50% * 90 = 45
1. 75% * 200 = 0.75 * 200 = 3/4 * 200 = 150
2. 10% * 8000 = 0.1 * 8000 = 800
1. 5% * 20 = 0.05 * 20 = 1
25x.25=6.25 so the answer is $6.25
Answer:

Step-by-step explanation:



