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Mumz [18]
3 years ago
7

A farmer has a field in the shape of a triangle. The farmer has asked the manufacturing class at your school to build a metal fe

nce for his farm. From one vertex, it is 435m to the second vertex and 656m to the third vertex. The angle between the lines of sight to the second and third vertices is 49 degrees. Calculate how much fencing he would need to enclose his entire field.
Mathematics
1 answer:
Iteru [2.4K]3 years ago
5 0

Answer:

The amount required is  l_t  =  1586 \ m

Step-by-step explanation:

From the question we are told that

   The length of one side is  l_1 =  435 \ m

    The length  of the second side is  l_2  =  656 \  m

     The angle between the line of sight of second and third side is  \theta  =  49^o \\

Generally using cosine rule the third side is evaluated as

     l_3^2 =  l_1 ^2  + l_2^2  -  2 * l_1  *  l_2  cos  (\theta )

=>    l_3^2  =  435 ^2  +  656^2  -  2 * 453* 656 cos (49)

=>   l_3  =  495 \  m

The total  amount of face required is  mathematically evaluated as

       l_t   = l_1  + l_2 + l_3

   l_t  =  435 +  656 +  495

   l_t  =  1586 \ m

     

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Find the product of 44.6 and 2.24.<br><br> (Show your work)
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Answer:

46.84

Step-by-step explanation:

Add the decimals first to get .84 then add the real numbers to get 46.

6 0
3 years ago
Can someone help with only the ones i circled?
stich3 [128]
3/4 cup of milk and 2 gallons.

Explanation: 1/4 • 3 becomes 3/4 and 2/5 times 5 becomes 10/5 which when simplified is 2! Hope this helps:)
8 0
3 years ago
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A car driving at 20m/s accelerates at 3m/s2 for 3s. What is its final velocity? How far will it travel during this time?
-BARSIC- [3]

Answers:

Final velocity = 29 m/s

Distance traveled = 73.5 meters

========================================================

Work Shown:

The given data is

v_i = 20 \text{ m}/\text{s} = \text{initial velocity}\\\\a = 3 \text{ m}/\text{s}^2 = \text{acceleration}\\\\t = 3 \text{ s} = \text{time duration}\\\\

This leads to

v_f = v_i + a*t\\\\v_f = 20 + 3*3\\\\v_f = 20 + 9\\\\v_f = 29\\\\

The final velocity is 29 m/s.

----------

We can use that final velocity to find the distance traveled.

x = 0.5*(v_i+v_f)*t\\\\x = 0.5*(20+29)*3\\\\x = 0.5*(49)*3\\\\x = 24.5*3\\\\x = 73.5\\\\

The distance traveled is 73.5 meters.

----------

An alternative way to calculate the distance is to do this

x = \frac{(v_f)^2 - (v_i)^2}{2a}\\\\x = \frac{(29)^2 - (20)^2}{2*3}\\\\x = \frac{841 - 400}{6}\\\\x = \frac{441}{6}\\\\x = 73.5\\\\

Or you could do this

x = v_i*t + 0.5*a*t^2\\\\x = 20*3 + 0.5*3*3^2\\\\x = 20*3 + 0.5*3*9\\\\x = 60 + 13.5\\\\x = 73.5\\\\

For more information, check out the Kinematics equations.

7 0
2 years ago
Plz help no guessing
Ierofanga [76]

90% sure the answer is A.

5 0
3 years ago
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Eggs are bought for 80c each and sold for R15 per dozen. What is the percentage profit (rounded off to the nearest percentage) ma
Mekhanik [1.2K]

The percentage profit made on the eggs is 56.25%

Data;

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  • Number of eggs = 1 dozen = 12 eggs
  • Selling price = R15

<h3>Percentage Profit</h3>

This is the ratio between the profit to the cost price multiplied by 100.

But 1 R = 100 cents

15 R = x

1R = 100c\\15R = x\\x = 15 * 100\\x = 1500c

The Cost price for 1 dozen is

80 * 12 = 960c

The cost price of the eggs is 960c

The percentage profit here will be

\% profit = \frac{selling price - cost price}{cost price} * 100\\\% profit= \frac{1500-960}{960}*100\\ \%profit = \frac{540}{960}*100\\ \% profit= 56.25 \%

The percentage profit made on the eggs is 56.25%

Learn more on selling price here;

brainly.com/question/19104371

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