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Vinvika [58]
3 years ago
9

How do I find the surface area of a cube? Please help! Thanks

Mathematics
1 answer:
timofeeve [1]3 years ago
8 0
A= 6x²

6 being the number of faces and x² being the length of one edge squared.
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A soccer field is a rectangle 60 meters wide and 110 meters long. The coach asks players to run from one corner of the grass fie
Wittaler [7]

Answer:

A

Step-by-step explanation:

A soccer field is a rectangle 60 meters wide and 110 meters long. The coach asks players to run from one corner of the grass field to the opposite corner. The path from one corner of the grass field to the opposite corner is the diagonal of the rectangular field.

The width, the length and the diagonal of the rectangular field form right triangle. By the Pythagorean theorem,

\text{Diagonal}^2=\text{Width}^2+\text{Length}^2\\ \\\text{Diagonal}^2=60^2+110^2\\ \\\text{Diagonal}^2=3,600+12,100\\ \\\text{Diagonal}^2=15,700\\ \\\text{Diagonal}=\sqrt{15,700}\approx 125\text{ yd}

6 0
3 years ago
Help find the domain and the range
erica [24]

Answer:

Step-by-step explanation:

domain:-all real numbers.

as y≥-2

so range is all real values ≥-2

6 0
4 years ago
[(x/x+3)+(3/x+3)+(2/x+3)] sum
nordsb [41]
You get the answer x+5/x+3.
This is because all of the fractions have the same denominator, so just add the numerators and put them over x+3.
8 0
3 years ago
Read 2 more answers
An open box with a square base is constructed so that it has a volume of 64in^3. The base needs to be made out of a material tha
Ivahew [28]

The volume of a box is the amount of space in the box

The dimensions that minimize the cost of the box is 4 in by 4 in  by 4 in

<h3>How to determine the dimensions that minimize the cost</h3>

The dimensions of the box are:

Width = x

Depth = y

So, the volume (V) is:

V = x^2y

The volume is given as 64 cubic inches.

So, we have:

x^2y = 64

Make y the subject

y = \frac{64}{x^2}

The surface area of the box is calculated as:

A =x^2 + 4xy

The cost is:

C = 2x^2 + 4xy --- the base is twice as expensive as the sides

Substitute y = \frac{64}{x^2}

C = 2x^2 + 4x * \frac{64}{x^2}

C =2x^2 +  \frac{256}{x}

Differentiate

C' =4x -  \frac{256}{x^2}

Set to 0

4x -  \frac{256}{x^2} = 0

Multiply through by x^2

4x^3 -  256= 0

Divide through by 4

x^3 -  64= 0

Add 64 to both sides

x^3 =  64

Take the cube roots of both sides

x = 4

Recall that:

y = \frac{64}{x^2}

So, we have:

y = \frac{64}{4^2}

y = 4

Hence, the dimensions that minimize the cost of the box is 4 in by 4 in  by 4 in

Read more about volume at:

brainly.com/question/1972490

4 0
3 years ago
You randomly select a card from a 52-card deck. What is the probability that the card is
krek1111 [17]

Answer: 39/52 or 3/4 or .75

Step-by-step explanation:

52-13=39

39 cards are not clubs

5 0
3 years ago
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