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3 years ago

0.3z - 0.02z + 0.2 = 1.8

1 answer:

4 0

Z=5.714285714285714 because you subtract 0.3z from 0.02z which = 0.28z and then subtract.2 from 1.8 which is 1.6. So then divide 1.6 by 0.28 to find z.

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Rewrite 4 6/7 as an improper fraction. sorry this is the correct question

goblinko [34]

The correct answer is, obviously, 34/7.

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4 years ago

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The Pythagorean theorem can only be used with witch type of triangle

HACTEHA [7]

Answer:

Right Triangles

Step-by-step explanation:

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2 years ago

The pack of 300 markers has a cost of $14.00. What is the UNIT COST for the markers? In other words, how much does each marker c

leva [86]

Answer:

Step-by-step explanation:

14/300=0.04

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3 years ago

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Which of the following are the zeros of the function y= 3(x-a)(x+b) in terms of a and b?

frosja888 [35]

The correct answer is option 2.

3 = 0

x - a = 0

x = a

x + b = 0

x = -b

We do not multiply any of these values by 3 because in a way, 3 is acting as another "zero" of the equation. Though, as shown above, it does not equal 0, it still does not apply to any of the other equations solved above.

Hope this helps!! :)

7 0

4 years ago

PLEASE!!!!!!!The adjoining figure shows two circles with the same center. The

Nookie1986 [14]

<h3>Answer:</h3>

$\boxed{\boxed{\pink{\sf \leadsto Hence \ the \ area \ of \ shaded \ region \ is 264 cm^2}}}$

<h3>Step-by-step explanation:</h3>

Here , two circles are given which are concentric. The radius of larger circle is 10cm and that of smaller circle is 4cm . And we need to find thelarea of shaded region.

From the figure it's clear that the area of shaded region will be the difference of areas of two circles.

Let the,

Radius of smaller circle be r .
Radius of smaller circle be r .
Area of shaded region be $\bf Area_{shaded}$

$\bf \implies Area_{Shaded}= Area_{bigger}-Area_{smaller} \\\\\bf\implies Area_{Shaded} = \pi R^2 - \pi r^2 \\\\\bf\implies Area_{shaded} = \pi ( R^2-r^2) \\\\\bf\implies Area_{shaded} = \pi [ (10cm)^2 - (4cm)^2] \\\\\bf\implies Area_{shaded} = \pi [ 100cm^2-16cm^2] \\\\\bf\implies Area_{shaded} = \pi \times 84cm^2 \\\\\bf\implies Area_{shaded} = \dfrac{22}{7}\times 84cm^2 \\\\\bf\implies \boxed{\red{\bf Area_{shaded} = 264 cm^2 }}$

<h3>Hence the area of the shaded region is 264 cm².</h3>

5 0

3 years ago