Simplify 5 log2 k – 8 log2 m + 10 log2 n ...?

2 answers:

5 0

The solution to the problem is as follows:

5log2(k) = log2(k^5) 
8log2(m)= log2(m^8) 
10log2(n)= log2(n^10) 
now to subtract logs, you divide the arguments, keeping the same vase. 
To add logs, multiply the arguments. 

So log2(k^5)- log2(m^8)+ log2(n^10)= log2[k^5* n^10)/m^8]


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Leno4ka [110]3 years ago

4 0

Answer:

your answer is log2 k to the fifth power n to the tenth power over m to the eighth power

Step-by-step explanation:

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