Answer:
Solution given:
b=9 base side of isosceles triangle
a=![\sqrt{9²+9²}=9\sqrt{2}](https://tex.z-dn.net/?f=%20%5Csqrt%7B9%C2%B2%2B9%C2%B2%7D%3D9%5Csqrt%7B2%7D)
Sum means add
(x+5) + (-4x-2) + (2x-1)
=-3x+3+(2x-1)
=-x+2
The correct answer is C
Hope this helped!
We can use the Pythagorean theorum
a^2+b^2=c^2
c^2 is the length of the longest side squared
so
6^2 + b^2 = 10^2
36+ b^2 = 100
-36 -36
b^2 = 64
b = 8
b is the same thing as your "x", so x = 8