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Stells [14]
3 years ago
7

What is the velocity of a skateboarder whose momentum is 100kg-m/s and the mass is 15kg?

Mathematics
2 answers:
Jobisdone [24]3 years ago
6 0

Answer:

6.67 m/s

Step-by-step explanation:

Ray Of Light [21]3 years ago
6 0

Answer : The correct option is, (D) 6.67 m/s

Explanation : Given,

Momentum = 100 Kg m/s

Mass = 15 Kg

Momentum : It is defined a the product of mass and the velocity of an object.

Formula used :

where,

p = momentum

m = mass

v = velocity

Now put all the given values in the above formula, we get the velocity of a skateboarder.

Therefore, the velocity of a skateboarder is, 6.67 m/s

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(2/3) - (7/12)
= .0834 
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6 0
3 years ago
e vertices of a rectangle are R(-5,-5), S(-6,-5),T(-1,1),U(-5,1) a translation maps R to the point (2,-9)
Tema [17]

Answer:

The rule of translation : (x,y)\rightarrow (x+7,y-4)

The vertices of image is R'(2,-9), S'(1,-9), T'(6,-3) and U'(2,-3).

Step-by-step explanation:

The vertices of a rectangle are R(-5,-5), S(-6,-5), T(-1,1), U(-5,1).

It is given that a translation maps R to the point (2,-9).

Difference between x-coordinates:

-5-2=-7

Difference between y-coordinates:

-5-(-9)=-5+9=4

The x-coordinate increased by 7 and y-coordinate decreased by 4. It means the figure shifts 7 units right and 4 units down.

The rule of translation is

(x,y)\rightarrow (x+7,y-4)

The vertices of image are

R(-5,-5)\rightarrow R'(-5+7,-5-4)=R'(2,-9)

S(-6,-5)\rightarrow S'(-6+7,-5-4)=S'(1,-9)

T(-1,1)\rightarrow T'(-1+7,1-4)=T'(6,-3)

U(-5,1)\rightarrow U'(-5+7,1-4)=U'(2,-3)

Therefore, the vertices of image are R'(2,-9), S'(1,-9), T'(6,-3) and U'(2,-3).

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PLEASE HELP!!
QveST [7]
Just add up all the numbers
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here's your answer:

Triangle ABC has vertices A(0,0), B(0,4), and C(3,0). Write the equation for the line containing altitude AR in standard...

brainly.com/question/8243985?utm_source=android&utm_medium=share&utm_campaign=question

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Answer:

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Step-by-step explanation:

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