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SVEN [57.7K]
3 years ago
6

How do you find the point slope form for the points (2,7) and (-1,9)?

Mathematics
2 answers:
iris [78.8K]3 years ago
8 0

Answer:

y = -2/3 x + 25/3

Step-by-step explanation:

The slope = (y_2 - y_1) / (x_2 - x_1) = (9 - 7) / (-1 - 2) = -2/3.

Our equation needs to be in y = mx + b form.

We can plug in (2, 7) as our (x, y) and find b:

7 = -2/3 (2) + b

b = 7 + 4/3 = 25 / 3.

Therefore, our equation is y = -2/3 x + 25/3

brilliants [131]3 years ago
3 0

Use the Equation(in the picture) and plug in your variables to find m(slope)

\frac{9-7}{-1-2} = \frac{-2}{3} = -0.67

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15y +5x- 7y+1x-3y i need help
vladimir2022 [97]

Answer:

simplify the expression: 6x+5y

Step-by-step explanation:

8 0
3 years ago
Name a pair of overlapping congruent triangles in each diagram. State whether the triangles are congruent by SSS, SAS, ASA, AAS,
MariettaO [177]

Answer:

ΔPTS≅ΔRTA by AAS axiom of congruency

Step-by-step explanation:

Consider ΔPQA and ΔRQS

∠PQA=∠RQS     (Vertically Opposite Angles)

∠QAP=∠QSR     (Complementary of two equal angles, ∠RAT and∠PST)

Due to angle sum property of a triangle, we come to the conclusion that

∠APQ=∠SRQ

Consider ΔPTS and ΔRTA

TA=TS  (Given)

∠RAT=∠PST(Given)

∠APQ=∠SRQ (Proved above)

Therefore, ΔPTS≅ΔRTA by AAS axiom of congruency.

8 0
3 years ago
Help me pleaseeee thank you sm
Leno4ka [110]

Answer:

The answer is A) 379.9

Step-by-step explanation:

3.14(11^2)

3.14*11^2

3.14*(11*11)

379.94 if rounded to the nearest tenth it would be 379.9

7 0
3 years ago
[4]
Tanya [424]

Answer:

Angle ACD = 38°

Step-by-step explanation:

The full, correct question is presented the attached image to this solution.

Given

Point O is the centre if the circle

Points A, B, C and D are points on the circle

Angle AOB = 140°

Angle OAC = 14°

Angle AOB = 2 × (Angle ACB) [angle subtended at the centre of the circle is twice the angle subtended at the circumference of the circle)

140° = 2 × (Angle ACB)

Angle ACB = (140°/2) = 70°

(Angle AOB) + (Angle OAB) + (Angle ABO) = 180° [sun of angles in a triangle is 180°]

But Angle OAB = Angle ABO = a [base angles of an iscosceles triangle are equal since OA and OB are both radii for the circle O)

(Angle AOB) + (Angle OAB) + (Angle ABO) = 180°

140° + a + a = 180°

2a = 40°

a = (40/2) = 20°

Angle OAB = Angle ABO = 20°

Angle CAB = (Angle OAC) + (Angle OAB) = 14° + 20° = 34°

Triangle ADC is an iscosceles triangle, hence,

Angle DAC = Angle ACD = x [base angles of an iscosceles triangle are equal]

But

(Angle DCB) + (Angle DAB) = 180° [Opposite angles of a cyclic quadilateral (a quadilateral inscribed in a circle) sum up to give 180°]

Angle DCB = (Angle DCA) + (Angle ACB) = (x + 70°)

Angle DAB = (Angle DAC) + (Angle CAB) = (x + 34°)

(Angle DCB) + (Angle DAB) = 180°

(x + 70°) + (x + 34°) = 180°

2x + 104° = 180°

2x = 180° - 104° = 76°

x = (76°/2) = 38°

Angle DAC = Angle ACD = 38°

Angle ACD = 38°

Hope this Helps!!!

7 0
3 years ago
Use an equivalent fraction to find the sum of 4/10 + 28/100
kipiarov [429]
Hi there!

4/10 = (4*10)/(10*10) = 40/100

40/100 + 28/100 = 68/100

68/100 = 34/50 = 17/25

Hope this helps!
4 0
3 years ago
Read 2 more answers
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