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4 years ago

Ow much fencing is required to enclose a circular gardan whose radius is 14m used 22 / 7 for pi

Mathematics

1 answer:

Musya8 [376]4 years ago

6 0

Answer:

87.92 m

Step-by-step explanation:

Formula for the circumference of a circle (which is what you're finding with this problem) is pi d

Pi being 3.14 and d being the diameter

Since the radius is 14 the diameter is 2 times that , 28m

Now just multiply 28 and 3.14 which gives you 87.92

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Use the following data to answer the question. 10, 9, 4, 7, 5.5 The range for this data is _____.

Novay_Z [31]

The range is the largest number minus the smallest number

10-4

=6

so 6 is your range

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4 years ago

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Graph this function using intercepts Solve 10x+9y=-90

Alex17521 [72]

Answer:

Step-by-step explanation:

So first, lets solve for the intercepts.

Let’s start by finding the x intercept.

Plug in 0 for y.

10x+9(0)=-90

10x=-90

X=-9, so your first point on your line will be (-9,0).

Now the y intercept.

Plug in 0 for x.

10(0)+9y=-90

9y=-90

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3 years ago

A website manager has noticed that during the evening hours, about 3.23.2 people per minute check out from their shopping cart

aleksandrvk [35]

Answer:

1. c. Poisson

2. 0.9592 = 95.92% probability that in any one minute at least one purchase is made.

3. 0.0017 = 0.17% probability that no one makes a purchase in the next 2 minutes.

Step-by-step explanation:

We have only the mean, which means that the Poisson distribution is used to solve this question, and thus the answer to question 1 is given by option c.

Poisson distribution:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

Mean of 3.2 minutes:

This means that $\mu = 3.2n$ , in which n is the number of minutes.

2. What is the probability that in any one minute at least one purchase is made?

$n = 1$ , so $\mu = 3.2$ .

This probability is:

$P(X \geq 1) = 1 - P(X = 0)$

In which

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-3.2}*3.2^{0}}{(0)!} = 0.0408$

$P(X \geq 1) = 1 - P(X = 0) = 1 - 0.0408 = 0.9592$

0.9592 = 95.92% probability that in any one minute at least one purchase is made.

3. What is the probability that no one makes a purchase in the next 2 minutes?

2 minutes, so $n = 2, \mu = 3.2(2) = 6.4$

This probability is P(X = 0). So

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-6.4}*6.4^{0}}{(0)!} = 0.0017$

0.0017 = 0.17% probability that no one makes a purchase in the next 2 minutes.

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3 years ago

You need 3 sticks of butter for every 24 cookies. If you have 5 sticks of butter how many cookies is that?

Ber [7]

Answer:

5:40

Step-by-step explanation:

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3 years ago

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Help please with this lol.

seraphim [82]

<h2>answer:</h2>

the value is $3.02

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3 years ago

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