Reflection over the y-axis:
(x, y) ⇒ (-x, y)
Reflection of that over the line y = x:
(-x, y) ⇒ (y, -x)
Rotation counterclockwise by 270°:
(x, y) ⇒ (y, -x) . . . . . . equivalent to reflection over y, then over y=x.
The appropriate choice is ...
C) Reflecting over the y-axis and then reflecting over the line y = x.
Answer:
![y=[1]cos([\frac{2\pi }{3}]x)](https://tex.z-dn.net/?f=y%3D%5B1%5Dcos%28%5B%5Cfrac%7B2%5Cpi%20%7D%7B3%7D%5Dx%29)
Step-by-step explanation:
Looking at the graph, we can see the domain to be from (0 , 2π).
Now we have to find one period that corresponds to cos(x).
The half-period of cos(x) for this graph appears to be pi/3 and adding another pi/3 gets us 2pi/3 to be our cosine period.
b = 2pi/3
a is the same range as cos(x). Range: (0,0)
y = [a] * cos ([b]*x)
y = [1] * cos([2pi/3]x)
Answer:
12
Step-by-step explanation:
The equation is:
1/2x+4x+6-1/2x-2
Ok so you can cancel out 1/2x and 1/2x because 1/2x-1/2x=0
You are left with:
4x+4
If you plug in 2 for x
4(2)+4=12
I hope this helps :)
Answer:
a.) (-16,0)(0,12)
b.) (-3,0)(0, 3/2)
Step-by-step explanation:
Plug it in for each.
y= 3/4x+12 (Lets plug in our x intercept of (x,0) and our y intercept of (0,y)
x-intercept
0=3/4x+12
-12 -12
-12=3/4x
-12/(3/4)=x
-16=x
SO, your x intercept is -16 which is point (-16, 0)
Now to do your y intercept in lets plug x in as 0 instead this time:
y = 3/4(0)+12
y = 12
Your y intercept is 12
Now for b its the same process of plugging 0 in for the values let
y-int=-2(0)-4y+6=0
-6 -6
-4y/-4=-6/-4 <- divide both sides by 4
y = 3/2 <- Simplified answer
y int = (0, 3/2)
x-int = -2x-4(0)+6 = 0
+6 +6
-2x = 6
x = 6/-2 <-- Divide both sides by -2
x = -3 <-- Simplify
x-int = (-3, 0)
Hey Giraffe111!
5280 ft= 1 mile
x ft= 3 mile
5280*3=15840 ft!
I hope this helps;)
