I believe y=x+2 and y=-x+3 are perpendicular lines.
The number of solutions of a quadratic equation
ax^2+bx+c=0
Depends on its discriminant
/Delta=b^2-4ac
If /Delta>0 there are two distinct solutions
If /Delta=0 there are two coincident solutions
If /Delta<0 there are no solutions.
We know that there are two real solutions (I assume you mean distinct solutions), so we know that the discriminant is positive:
The number of solutions of a quadratic equation
Depends on its discriminant
If there are two distinct solutions
If there are two coincident solutions
If there are no solutions.
We know that there are two real solutions (I assume you mean distinct solutions), so we know that the discriminant is positive:
b^2-4ac=9+28t>0\iff t>-\dfrac[9][28]
Answer:
the first blank is 2, the second one is 1
21x - 14
Explanation:
you distribute the 7, and first multiply it by 3x to get 21x. Then you distribute the 7 and multiply it by the -2 to get -14.
Hope this helps!
