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4 years ago

Please simplify the expression.

Mathematics

1 answer:

IRINA_888 [86]4 years ago

8 0

Answer:

1) 15a - 15c + 3

2) -7n + 31 + 13m + 7p or 13m - 7n + 7p + 31

3) 44x + 6y + 3

4) 9m - 6n + 23

Step-by-step explanation:

1. Add like terms. 6a + 9a=15a. -8c - 7c=-15c

2. Add like terms. You can rearrange them in descending order based off of exponents and variables.

3. Multiply what's in parentheses first (distribute the 6). It should end up being (6y + 42x). Then you add like terms and put in descending order.

4. Distribute the (-3) to what in the parentheses. It should end up being (-6n + 15 - 3m). Then you add like terms and put the expression in descending order.

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3 years ago

Read 2 more answers

Choose the correct answer from the given four options:In an AP if a = –7.2, d = 3.6, an = 7.2, then n

Serggg [28]

Answer:

n=5

Step-by-step explanation:

by using

n=(an-a)/a+1

substituting values

n= 7.2-(-7.2)/3.6 +1

n=5

5 0

3 years ago

If three pears and four oranges cost $4.85 and three pears and ten oranges cost $8.75 what is the cost of a pear and an orange

marishachu [46]

Answer:

1 pear = $0.75; 1 orange = $0.65

Step-by-step explanation:

(1) 3P + 4O = 4.85

(2) 3P + 10O = 8.75 Eqn (2) - Eqn (1)

3P + 10O – 3P – 4O = 8.75 – 4.85 Combine like terms

6O = 3.90 Divide each side by 6

O = $0.65 Substitute into Eqn (1)

3P + 4×0.65 = 4.85

3P + 2.60 = 4.85 Subtract 2.60 from each side

3P = 2.25 Divide each side by 3

P = $0.75

Oranges cost $0.65 each and pears are $0.75 each

4 0

3 years ago

A figure is composed of a rectangle and a right triangle. What is the area of the figure?

strojnjashka [21]

QUESTION 1

The figure is a tra-pezoid.

The area of a trapezoid is given by the formula;

$A=\frac{1}{2}(Sum\:of\:parallel\:sides)\times h$

We substitute the values to obtain;

$Area=\frac{1}{2}(13.2cm+8.4cm)\times 6cm$

$Area=\frac{1}{2}(21.6cm)\times 6cm$

$Area=64.8cm^2$

QUESTION 2

The approximate length of the ribbon is equal to the circumference of the circular table cloth.

We can find this by using the formula for calculating the circumference of a circle.

$C=2\pi r$

where $r=3.5ft$ is the radius of the circular table cloth.

We substitute this value and $\pi=3.14$ into the formula to get;

$C=2(3.14)(3.5)ft$

$C=21.98ft$

The approximate length of the ribbon is 22.0ft to the nearest tenth.

QUESTION 3

Type of quadrilateral:Rectangle

Explanation: A rectangle has 4 angles that are right angles.

The two pairs of opposite sides of a rectangle are also congruent.

QUESTION 4.

The circumference of a semi circle is calculated using the formula;

$C=\pi r$

where $r=12.5cm$ is the radius of the semicircle.

$C=3.14\times 12.5cm$

$C=39.25cm$

QUESTION 5

The area of the entire figure is the area of the semicircle plus the area of the isosceles triangle.

$Area=\frac{1}{2}\pi r^2+\frac{1}{2}bh$

$Area=\frac{1}{2}\times3.14\times12.5^2+\frac{1}{2}\times25\times 24$

$Area=345.3125+300$

$Area=645.3125cm^2$

$Area\approx645cm^2$

QUESTION 6

The area of the parallelogram is given by the formula;

$A=bh$

From the diagram, $b=y\:in.,h=3in.$ .

Given, A=23.7 inches squared.

We substitute the values to obtain;

$23.7=3y$

$y=\frac{23.7}{3}$

$y=7.9in.$

QUESTION 7

The area of a rectangle is given by the formula;

$Area=l\times b$

The area of the bigger rectangle $=9\times15=135in^2$

The area of the smaller rectangle $=8\times 13=104in^2$

The area of the shaded region $=135-104=31in^2$

5 0

4 years ago

One side of a triangle is two times the second side. The third side is 5 feet longer than the second side. The perimeter of a tr

Sphinxa [80]

Second side= x
First side = 2x
Third side = x+5
x+2x+x+5=49
4x=44
x=11

1st side= 22
2nd side = 11
3rd side = 16

3 0

3 years ago