Using the table, what is the relative frequency of the blue beads?

A company offers its employees the choice of two contracts. The first contract gives an initial salary of 15000/year rising it b

sladkih [1.3K]

To answer this question, start by identifying the total amount of income after 5 years for the first contract.
Since you start with 15,000 and get 1000 more each year, write an expression that represents this relationship.
15000 + 1000(5)

Multiply the parenthesis to begin to simplify your expression.
This leaves you with:
15000 + 5000

Add to find the total salary after five years with the first contract.
This ends up with:
$20,000

For the second contract, you have a diffferent rate of increase. Start by finding what one percent of the initial salary is. To do this, divide 14000 by 100.
14000/100 = 140
Then to find ten percent, multiply that number by 10.
140 x 10 =1400

So, each year you add 1400 dollars to the salary.
Now, using this information, set up an expression to model the salary for contract 2 after 5 years.
This should leave you with:
14000 + 1400(5)

Begin to simplify by multiplying what’s in the parenthesis.
1400 x 5 = 7000
Now rewrite your expression:
14000 + 7000

Add to find the total salary after 5 years with contract 2.
14000 + 7000 = 21000

So the salary with contract 2 is $21,000.

So, since $21000 is $1000 more than just $20000, contract 2 is the better option. I hope this helps! :)

5 0

3 years ago

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This parabola has<br> x-intercepts

slega [8]

Answer:

see the explanation

Step-by-step explanation:

we have the quadratic equation

$y=-16x^{2} +32x-10$

This is a vertical parabola open downward

The vertex is a maximum

Find the x-intercepts of the quadratic equation

The x-intercepts are the values of x when the value of y is equal to zero

so

For y=0

$-16x^{2} +32x-10=0$

Solve the quadratic equation

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$-16x^{2} +32x-10=0$

so

$a=-16\\b=32\\c=-10$

substitute in the formula

$x=\frac{-32(+/-)\sqrt{32^{2}-4(-16)(-10)}} {2(-16)}$

$x=\frac{-32(+/-)\sqrt{384}} {-32}$

$x=\frac{-32(+/-)8\sqrt{6}}{-32}$

$x=\frac{-32(+)8\sqrt{6}}{-32}=\frac{32(-)8\sqrt{6}}{32}=0.39\ sec$

$x=\frac{-32(-)8\sqrt{6}}{-32}=\frac{32(+)8\sqrt{6}}{32}=1.61\ sec$

therefore

This parabola has two x-intercepts representing the times when the dolphin's height above water is zero feet

8 0

3 years ago

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use each of the digits 2,3,5,8 once with any combination of +,-,., or () to write an expression with a value of 104

densk [106]

8 times 13 = 104

8 * ( 5*3 - 2) = 104

4 0

3 years ago

Clare is painting some doors that are all the same size. She used 2 liters of paint to cover 1 and 3/5 doors. How many liters of

vitfil [10]

Answer:

1 and 1/4 liters of paint are needed for one door

Step-by-step explanation:

You can eliminate each answer choice out. For '4/5 liters' you know that if that amount was used, it wouldn't be reasonable since it would mean that the more was used for the other 3/5 door. 3 and 1.5 would be too much since it is over 2 liters. 2 liters wouldn't be logical since you paint 1 <em>and</em> 3/5 of a door and you only used 2 liters, no more or no less, basically what would you use for the other 3/5 door if this was the answer.

Hope this helps!

4 0

3 years ago

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Consider:

astraxan [27]

Answer:

C

Step-by-step explanation:

6 0

3 years ago