Question

Suppose I pick a jelly bean at random from a box containing one red and eleven blue ones. I record the color and put the jelly bean back in the box.
If I do this three times, what is the probability of getting a blue jelly bean each time? (Round your answer to three decimal places.)

Answer 1

Answer:

0.770

Step-by-step explanation:

a box containing one red and eleven blue ones

Total 1 red +11 blue = 12 jelly beans

we pick a jelly bean at random from a box .We record the color and put the jelly bean back in the box.

Probability of picking a blue jelly is number of blue jelly divide by total

$P(blue)= \frac{11}{12}$

Blue is replaced back in the box

$P(another blue)= \frac{11}{12}$

$P(another blue)= \frac{11}{12}$

Probability of getting blue each time =

$\frac{11}{12} \cdot \frac{11}{12} \cdot \frac{11}{12} =\frac{1331}{1728} =0.770$

Answer 2

Answer:

1.09 i believe.

Step-by-step explanation:

you do 12 (the total number) divided by 11 ( the number of blues) and that’s the answer