Answer with Step-by-step explanation:
Since we have given
n = 16
a) Describe the sampling distribution for the sample mean.
The sampling distribution of the mean is the population's mean from where the items are sampled.
It would be
b. What is the standard error?
c. For 90% confidence, what is the margin of error?
Degrees of freedom = v - 1= 16-1 = 15
Using t-table, 1.753 cuts 5% level of significance in each tail.
so, Margin of error would be
d. Based on the sample results, create the 90% confidence interval and interpret.
So, 90% confidence interval would be
(103.86,116.136)