Here speed of first train is slower than speed of second train. So if they catch up , the distance traveled will be same since they left the same station at different times.
But the time traveled will be different .
Let us say the two trains meet at time t ,
Distance = speed * time
Distance traveled by first train = 40 t
Since second train is leaving after three hours , so
Distance traveled by second train = 60(t-3)
As discussed earlier, distance traveled will be same, so
distributing 60 over t-3
t=9
So the second train will meet the first at 9 p.m.
To find the percentage,here's what we can do:
The percentage would then be:
=63/420×100%
=3/20×100%
=0.15×100%
=15%
Therefore the answer is 15%.
Hope it helps!
Answer:
58.1 degrees
Step-by-step explanation:
Given the following
JK = 9.4miles (towards south) negative y axis
If the move 15.1 miles towards east (that will be towards the positive x axis)
Using the SOH CAH TOA identity
opposite= 15.1 miles(side facing m<J)
adjacent= JK = 9.4miles
tan theta = opposite/adjacent
tan m<J = 15.1/9.4
tan m<J = 1.6063
m<J = arctan (1.6063)
m<J = 58.09 degrees
Hence the measure of m<J to the nearest tenth is 58.1 degrees
Answer:
The solution is given below:
Step-by-step explanation:
The computation is shown below:
= 19 + 7 divided by 2 - 5
= (19 + 7) ÷ (2) - 5
= 26 ÷ 2 - 5
= 13 - 5
= 8
Hence, after solving this the value would be 8
Therefore it is equal to the 8
Hence, the given statement is true
Answer:
Cheyenne has a part-time job at which she gets paid by the hour. The table below shows how much money Cheyenne can earn for working variousCheyenne has a part-time job at which she gets paid by the hour. The table below shows how much money Cheyenne can earn for working various
Step-by-step explanation:
